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Aloiza [94]
3 years ago
7

Ray creates an energy transfer diagram for a hair dryer. However, the diagram contains an error that could be corrected in sever

al different ways.
Which of these changes would make the diagram error-free? Check all that apply.

1. reducing the amount of thermal energy to 475 J
2. increasing the amount of electrical energy to 825 J
3. increasing the amount of sound energy to 225 J
4. reducing the amount of kinetic energy to 50 J
5. reducing the amount of electrical energy to 675 J

Physics
2 answers:
Anettt [7]3 years ago
4 0

The 1st, 2nd, and 4thoptions are right :)

Tasya [4]3 years ago
3 0

The correct answer is 1,2,4.

Option 1

Since the hair drier does not create any energy, the sum of the input energy has to be equal to the sum of the output energy. The input energy is 750J. In this case,  sound energy is 150J and the kinetic energy is 125J. When the thermal energy is 475J, the output energy is,

475J+150J+125J=750J.

In this case, the diagram is error free.

Option 2

In this option, the input energy is 825J .The sum of the input energy has to be equal to the output energy. The sum of the output energy is calculated as shown below,

125J+150J+550J=825J.

In this situation, the diagram is error free because energy is conserved.

option 4

The input energy into this system is 750J. When the kinetic energy is reduced to 50J, the output energy of the drier is then,

50J+150J+550J=750J.

In this case, energy conservation is not violated, the input energy is equal to the output energy.


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Air in the amount of 2 lbm is contained in a well-insulated, rigid vessel equipped with a stirring paddle wheel. The initial sta
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Explanation:

It is known that energy balance relation is as follows.

           \Delta E_{system} = E_{in} - E_{out}

Also,   W_{in} = \Delta U

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According to the ideal gas equation,

           T_{2} = T_{1} \frac{P_{2}}{P_{1}}

Putting the values into the above equation as follows.

             T_{2} = T_{1} \frac{P_{2}}{P_{1}}

                         = (520R) \frac{40psia}{30psia}

                         = 693.3 R

Now, we will convert the temperature into degree Fahrenheit as follows.

            693.3 - 458.67

          = 234.63^{o}F

From table A-2E_{a}

 C_{p} = 0.240 Btu/lbm R  and   C_{v} = 0.171 Btu/lbm

Now, we will substitute the energy balance as follows.

            W_{in} = mC_{v}(T_{2} - T_{1})  

                         = 2 lbm \times 0.171 Btu/lbm R (693.3 - 520)

                         = 59.3 Btu

Thus, we can conclude that final temperature of air is 59.3 Btu.

6 0
4 years ago
Mixing baking soda with vinegar is an example of an oxidation-reduction
34kurt

Answer:

B. False

Explanation:

The reaction of baking soda and vinegar produces carbon dioxide gas. It is an example of precipitation reactions.

4 0
3 years ago
Assume biological substances are 90 percent water and the density of water is 1.0 ✕ 103 kg/m3.
Mariulka [41]
I think its 1x^103 (kg/m.3) I hope this help
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3 years ago
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
Marrrta [24]

Answer:

153.6 kN

Explanation:

The elastic constant k of the block is

k = E * A/l

k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m

0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

Where x is the change in length

F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

The smallest admisible load is 153.6 kN

8 0
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Answer:

B and A

Explanation:

6 0
3 years ago
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