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Nookie1986 [14]

3 years ago

5

A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the

1 answer:

vitfil [10]3 years ago

7 0

Answer:

F₂ = -7.3 N

Explanation:

Given that,

The mass of an object, m₁ = 3.7 kg

First force, F₁ = 11 N

The net acceleration of the object is 1 m/s².

We know that,

F₁+F₂ = ma

11+F₂ = (3.7)(1)

F₂ = 3.7-11

F₂ = -7.3 N

so, the other force is 7.3 N and it is acting in west direction.

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OlgaM077 [116]

$\frac{1}{4} = 0.25 = 25\%$

6 0

3 years ago

The table shows information about four students who are running around a track. Which statement is supported by the information

murzikaleks [220]

Answer:

Mohammed has less kinetic energy than Autumn

Explanation:

The kinetic energy of each student is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the student

v is the speed of the student

Let's use the formula above to calculate the kinetic energy of each student:

- Autumn: $K=\frac{1}{2}(50 kg)(4 m/s)^2=400 J$

- Mohammed: $K=\frac{1}{2}(57 kg)(3 m/s)^2=256.5 J$

- Lexy: $K=\frac{1}{2}(53 kg)(3 m/s)^2=238.5 J$

- Chiang: $K=\frac{1}{2}(64 kg)(5 m/s)^2=800 J$

Therefore, by looking at the numbers, we see that the correct answer is

Mohammed has less kinetic energy than Autumn

7 0

3 years ago

Read 2 more answers

He blocked his man using a force of 23 N moving him backward 2 meters ,how much work did he do?

Paul [167]

Answer:

work done = force x distance

Explanation:

F = 23 N

D = 2m

W = 23 * 2 = 46 J

6 0

4 years ago

How do I solve the equation

ioda

First you see the difference in mass numbers 238-234 = 4
Its is an alpha particle as it decreases the mass no by 4 .

6 0

3 years ago

The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca

Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

$D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J$

Calculating point A:

when the value is $0.38$

$\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\$

$=2.632$

$\to D(a.v) = \frac{1}{0.38} \times 206265\\$

$=542,802.6$

Calculating point B:

when the value is $0.75$

$\to D(PC)=\frac{1}{0.75}$

$=1.33$

$\to D(a.v) = \frac{1}{0.75} \times 206265\\$

$=275,020$

Calculating point C:

when the value is $0.28$

$\to D(PC)=\frac{1}{0.28}$

$=3.571$

$\to D(a.v) = \frac{1}{0.28} \times 206265\\$

$=736660.7$

Calculating point D:

when the value is $0.42$

$\to D(PC)=\frac{1}{0.42}$

$=2.38$

$\to D(a.v) = \frac{1}{0.42} \times 206265\\$

$=490910.7$

Calculating point E:

when the value is $0.31$

$\to D(PC)=\frac{1}{0.31}$

$=3.226$

$\to D(a.v) = \frac{1}{0.31} \times 206265\\$

$=665370.97$

6 0

3 years ago