An attack helicopter is equipped with a 20- mm cannon that fires 87 g shells in the forward direction with a muzzle speed of 853
2 answers:
Answer:
4457.7 N
Explanation:
87g = 0.087kg
v = 853m/s
t = 2.93 s
total mass hitting = m = 0.087*176 = 15.32 kg
net momentum = mv = 15.32*853 = 13061 kg.m/s
as we know the rate of change of momentum is the average force of impact,
F_avg = =
= 4457.7 kg.m/s^2 = 4457.7 N
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a =
a=
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
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Answer:
The x-component of the electric field at the origin = -11.74 N/C.
The y-component of the electric field at the origin = 97.41 N/C.
Explanation:
<u>Given:</u>
- Charge on first charged particle,
- Charge on the second charged particle,
- Position of the first charge =
- Position of the second charge =
The electric field at a point due to a charge at a point
distance away is given by
where,
= Coulomb's constant, having value
= position vector of the point where the electric field is to be found with respect to the position of the charge
.
= unit vector along
The electric field at the origin due to first charge is given by
is the position vector of the origin with respect to the position of the first charge.
Assuming, are the units vectors along x and y axes respectively.
Using these values,
The electric field at the origin due to the second charge is given by
is the position vector of the origin with respect to the position of the second charge.
Using these values,
The net electric field at the origin due to both the charges is given by
Thus,
x-component of the electric field at the origin = -11.74 N/C.
y-component of the electric field at the origin = 97.41 N/C.