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fgiga [73]
3 years ago
5

A volleyball is dropped from a cliff and a soccer ball is thrown upward from the same position. When each ball reaches the groun

d at the bottom of the cliff, the volleyball will hit the ground with greater velocity.
Physics
1 answer:
vredina [299]3 years ago
6 0
The question is whether the statement is true or false.

The answer if false.

Explanation:

It is exactly the opposite. The soccer ball will hit the ground with greater velocity.

Since the soccer ball is thrown upward, when it returns to the same heigth from which it was throwm it will have a velocity downward, which will make that the soocer ball reaches the ground at the bottom of the clif with greater velocity than the volleball.

The greater the velocity with which the soccer ball is thrown upward, the greater its velocity when reaches the same point from which it was thrown, and the greater the velocity with which it will hit the ground at the bottom of the clif.
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What properties of the wave define why it is found within this area of the spectrum?
MatroZZZ [7]

Answer:

Explanation:

Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;

Their medium of propagation

They both travel at the same speed ( speed of light )

The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.

Wish I Could Help You!

7 0
2 years ago
44. ( John weighs 80 kg, and eats a 1,000 J candy bar. If his
Darina [25.2K]

John can run with the velocity of 5 m/s

Explanation:

  • Kinetic energy is defined as the energy is being used to do an activity, basically energy associated with the motion of objects in the universe.
  • The formula used to find the kinetic energy of an object is k = \frac{1}{2} mv^{2} where as k represented as kinetic energy, m is the mass of the object and v is the velocity of the given object.
  • Here, to find the answer we have to re-write the equation as v = \sqrt[2]{\frac{2 k}{m} }
  • Given, the mass of the object, here it is John = 80 kg, energy needs to be converted to kinetic energy, k = 1000  J.
  • Hence, substitute all the values, then you would velocity as 5 m/s

4 0
4 years ago
Two objects have the same momentum. Do the velocities of these objects necessarily have (a) the same directions and (b) the same
NeX [460]

Answer:

(a) They must have same direction

(b) It is not necessary for them to have same magnitudes

Explanation:

(a)

Momentum is a vector quantity. It is the product of mass (scalar) and velocity (vector). Thus, if the direction of velocity is changed, then as a result the direction of momentum will also change or its magnitude or component in the same direction will change. Hence, for the two objects to have same momentum, the directions of their velocities must also be the same.

(b)

Since, the momentum is product of velocity and mass. It is possible that two bodies of different masses with different velocities might have same momentum, provided the direction of their velocities is same.

For example, take a body of mass 4 kg moving with speed 5 m/s. It will have a momentum of 20 N.s. Now, consider another body of mass 2 kg, moving with speed 10 m/s. It will also have a momentum of 20 N.s.

Thus, it is not necessary for two objects to have same magnitude of velocity to have same momentum.

3 0
3 years ago
Winding roads are made on hills, why?​
FromTheMoon [43]
Answer.

The road on the hills goes upward with the increasing length of the road.That's why we make a winding roads because it reduces the allover surface inclination in every portion of the road which is suitable for driving the vehicles.
3 0
3 years ago
A motorcycle, which has an initial linear speed of 8.0 m/s, decelerates to a speed of 2.2 m/s in 4.1 s. Each wheel has a radius
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Initial linear speed v_1=8 m/s

initial angular velocity \omega _1=\frac{v_1}{r}=\frac{8}{0.6}=13.33 rad/s

Speed after 4.1 s is  v_2=2.2 m/s

\omega _2=\frac{2.2}{0.6}=3.66 rad/s

using \omega _2=\omega _1+\alpha t

where \alphais angular acceleration

3.66=13.33+\alpha \cdot 4.1

\alpha =-2.37 rad/s^2 i.e. clockwise

(b)angular displacement

\theta =\omega _1t+\frac{\alpha t^2}{2}

\theta =13.33\times 4.1-\frac{2.37\cdot 4.1^2}{2}

\theta =54.66-19.75

\theta =34.91 rad

3 0
4 years ago
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