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3 years ago

Help. Please! I really need help. It’s timed, and I’m loosing points.

Physics

1 answer:

Archy [21]3 years ago

5 0

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

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Please describe the relationship between the lithosphere and asthenosphere making sure to incorporate these terms: divergent bou

Brilliant_brown [7]

Ithoshpere is space sheeld. asthenosphere next sheets of sky

8 0

4 years ago

Which of the following can be contracted from contact with bloodborne pathogens?

sergij07 [2.7K]

HIV can be contracted from contact with bloodborne pathogens.

Other bloodborne diseases are HBV, malaria, syphilis and brucellosis

<h3>What are bloodborne pathogens?</h3>

Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.

Blood borne pathogens can also be contacted through the following means

Se- xual contact
Needle contact

In conclusion; HIV can be contracted from contact with bloodborne pathogens.

Learn more about bloodborne pathogens:

brainly.com/question/13158004

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6 0

2 years ago

The components of vector A are Ax and Ay (both positive), and the angle that it makes with respect to the positive x axis is θ.

DIA [1.3K]

Answer:

a) $\theta = tan^{-1} (\frac{11}{11})= tan^{-1} (1)=45$ degrees

b) $\theta = tan^{-1} (\frac{11}{19})= tan^{-1} (0.579)=30.07$ degrees

c) $\theta = tan^{-1} (\frac{19}{11})= 59.93$ degrees

Explanation:

If we have a vector $A= (A_x ,A_y)$ in a two dimensional space. The angle respect the x axis can be founded from the following expression:

$tan (\theta)= \frac{A_y}{A_x}$

And then the angle is given by:

$\theta = tan^{-1} (\frac{A_y}{A_x})$

Part a

Ax = 11 m and Ay = 11 m

For this case the angle would be:

$\theta = tan^{-1} (\frac{11}{11})= tan^{-1} (1)=45$ degrees

Part b

Ax = 19 m and Ay = 11 m

For this case the angle would be:

$\theta = tan^{-1} (\frac{11}{19})= tan^{-1} (0.579)=30.07$ degrees

Part c

Ax = 11 m and Ay = 19 m

For this case the angle would be:

$\theta = tan^{-1} (\frac{19}{11})= 59.93$ degrees

8 0

3 years ago

Read 2 more answers

What would a boats velocity be if it would go 15kph and 18 kph?

Butoxors [25]

The equation to work out acceleration would be the final velocity subtract the start velocity divided by the time. So... in order to answer the question we would need the time taken.

8 0

3 years ago

Read 2 more answers

Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i

Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

$L = L_i_n_i + L_3_s$