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Alex777 [14]
3 years ago
5

Help. Please! I really need help. It’s timed, and I’m loosing points.

Physics
1 answer:
Archy [21]3 years ago
5 0

Answer:

I think balanced

Explanation:

because there is a 2 on each arrow

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Perfect square of 11650​
suter [353]

Answer:

Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.

The square root of 11650 is 107.935166.

One side of the square is 107.935166

107.935166 x 107.935166 = 11650

(っ◔◡◔)っ ♥ Hope It Helps ♥

7 0
2 years ago
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A proton is observed to have an instantaneous acceleration 11*10^11. what is the magnitude of e of the electric field at the pro
jek_recluse [69]

The magnitude of the electric field at the proton's location is 10,437.5 N/C.

<h3>What the magnitude of the electric field?</h3>

The size of the electric field is basically characterized as the power per charge on the test charge. On the off chance that the electric field strength is meant by the image E. Very much like gravity, electric fields work the same way. In any case, while gravity generally draws in, an electric field, then again, can either rebuff or draw in. By and large, the Electric Field submits to the super-position guideline. the all out Electric Field from various charges is equivalent to the amount of the electric fields from each charge separately. An electric field is the actual field that encompasses electrically charged particles and applies force on any remaining charged particles in the field, either drawing in or repulsing them.

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6 0
1 year ago
Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.
lisov135 [29]
Using formula: 
I=(1/2)*M*(R^2+r^2) 

<span>I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2] </span>

<span>I=98.6 kg*cm^2</span>
7 0
2 years ago
Calculate the gravitational potential energy of 3kg book sitting on shelf 4m high
likoan [24]

Answer:

i know it i know it pick me

Explanation:

5 0
3 years ago
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The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including
velikii [3]

Answer:

180^2 + 390^2 = force ^2 (Pythagoras) root of force^2 = 429.5N approx resultant force Acceleration = Force/Mass 429.5/270 = 1.5907 ms^-2 in a Southwesterly direction.

Explanation:

4 0
2 years ago
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