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TiliK225 [7]
3 years ago
11

An apple with a mass of 0.95 kilograms hangs from 3.0 meters above the ground. What is the potential energy of the apple

Physics
1 answer:
Vesnalui [34]3 years ago
3 0

As Potential energy =mgh

m= 0.95kg

h=3 meter

g = 9.8 m/sec^2. ( acceleration due to gravity)

So P.E =(0.95)(9.8)(3)kgm^2/s^2

P.E =27.93 joules

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Answer:

v = 23.66 m/s

Explanation:

recall that one of the equations of motion may be expressed:

v² = u² + 2as,

Where

v = final velocity (we are asked to find this)

u = initial velocity = 0 m/s since we are told that it starts from rest

a = acceleration = 0.56m/s²

s = distance traveled = given as 500m

Simply substitute the known values into the equation:

v² = u² + 2as

v² = 0 + 2(0.56)(500)

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v = 23.66 m/s

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Answer:

<u>Facts about 258</u>

<u>Sig Figs</u>

3

<u>258</u>

<u>Decimals</u>

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<u>Scientific Notation</u>

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<u>E-Notation</u>

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<u>Words</u>

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