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3 years ago

An apple with a mass of 0.95 kilograms hangs from 3.0 meters above the ground. What is the potential energy of the apple

Physics

1 answer:

Vesnalui [34]3 years ago

3 0

As Potential energy =mgh

m= 0.95kg

h=3 meter

g = 9.8 m/sec^2. ( acceleration due to gravity)

So P.E =(0.95)(9.8)(3)kgm^2/s^2

P.E =27.93 joules

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Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of

navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0

3 years ago

2. A student drives 7.8-km trip to school and averages a speed of

Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

$\displaystyle V=\frac{x}{t}$

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

$\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec$

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

$\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec$

The total time is:

$t=239.26\ sec+211.96\ sec=451.22\ sec$

$\boxed{t=451.22\ sec}$

The average speed is:

$\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s$

$\boxed{\displaystyle V=34.57\ m/s}$

6 0

3 years ago

Leonard is stressed and feeling overwhelmed by the college selection process. What should he do to combat this problem?

exis [7]

He should ask other people for advice

6 0

3 years ago

ou are looking for a new tennis partner. Which of these people would most likely demonstrate good sportsmanship based on the inf

Dennis_Churaev [7]

<h2><u>Answer:</u></h2>

As you are looking for a new tennis partner. People should keep in mind that they should go for the one who most likely demonstrate good sportsmanship

Luis, when you pursue the principles in tennis, you realize when to talk up, you don't blast a racquet or shout, holler.

Whatever it is following the principles and being respectful it the most ideal approach.

7 0

3 years ago

You are driving to the grocery store at 18 m/sm/s. You are 160 mm from an intersection when the traffic light turns red. Assume

inysia [295]

Answer:

part(a) 151 m

part(b) 1.073 m/s2

part(c) 16.7 secs

Explanation:Firstly the person applied brakes 0.5 secs after seeing the red light hence the distance traveled during this time is

d=v*t

d=18*0.5

d=9m

For part (a)

I have corrected this question and now

The person was 160m from the intersection before applying the brakes as he traveled 9m before the brakes

He is now 151 m from intersection as

s=160-9

s= 151 m

part (b)

As it is given that velocity of the car is 0 at the intersection so we use this information in kinematic equation

$v^2=u^2+2as$

here u=18m/s and s=151

$0=18^2+2a*151\\302a=-324\\a=-1.073 m/s^2$

To calculate time we can use the acceleration equation

$a=\frac{v-u}{t} \\t=\frac{v-u}{a}\\t=18/1.073\\t=16.77 secs$

6 0

3 years ago