Question

The magnetic flux that passes through one turn of a 18-turn coil of wire changes to 4.5 wb from 13.0 wb in a time of 0.072 s. the average induced current in the coil is 190
a. what is the resistance of the wire?

Answer 1

We could answer the question through the help of Faraday's Law of Induction: 

Volts induced = - N•dΦ/dt

where N is the number of turns, and

Φ is the magnitude of the magnetic field. 

V = IR, or R = V / I 

V = -18 * [13Wb – 4.5Wb] / 0.072s 

V = -2125 volts the sign just specifies direction 

R = -2125V / 190 A 

R = -11.1842105 Ω