A 60.0 N circus performer performs a high wire act 5.0 m above ground. About how much gravitational potential energy does the pe
rformer have?
2 answers:
Answer:
300 J
Explanation:
The gravitational potential energy of the performer is given by:
where
(mg) is the weight of the performer, equal to the product between mass (m) and gravitational acceleration (g)
h is the height of the performer above the ground
In this problem, we have
(mg) = 60.0 N
h = 5.0 m
Substituting into the formula, we find
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Answer:
L = 5076.5 kg m² / s
Explanation:
The angular momentum of a particle is given by
L = r xp
L = r m v sin θ
the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1
as we have two bodies
L = 2 r m v
let's find the distance from the center of mass, let's place a reference frame on one of the masses
=
i
x_{cm} =
x_{cm} =
x_{cm} =
x_{cm} = 13.1 / 2 = 6.05 m
let's calculate
L = 2 6.05 74.3 5.65
L = 5076.5 kg m² / s
To solve this problem it is necessary to apply the definition of severity of Newtonian laws in which it is specified that gravity is defined by
Where
G= Gravitational Constant
M = Mass of Earth
R= Radius from center of the planet
According to the information we need to find the gravity 350km more than the radius of Earth, then
Therefore the gravitational acceleration at 350km is