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Effectus [21]
4 years ago
12

20% Part (a) Use an "E Field Sensor" and move it along either equipotential. What can you say about the E field along an equipot

ential?
a. Varies in magnitude and direction, parallel to the equipotential.
b. Constant magnitude, but varying direction, perpendicular to the equipotential.
c. Varies in magnitude and direction, perpendicular to the equipotential.
d. Constant direction, but varying magnitude, perpendicular to the equipotential.
e. Constant direction, but varying magnitude, parallel to the equipotential.
f. Constant magnitude, but varying direction, parallel to the equipotential.
Physics
1 answer:
Alex4 years ago
6 0

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

\Delta E = -\frac{dV}{dr}

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

Then we will say

V = constant

so we have

\Delta E = 0

so electric field will remain constant always in magnitude and always remains perpendicular to the surface

so we have

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

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Calcite (CaCO_3) is a crystal with abnormally large birefringence. The index of refraction for light with electric field paralle
katrin2010 [14]

Answer:

(a) 42.28°

(b) 37.08°

Explanation:

From the principle of refraction of light, when light wave travels from one medium to another medium, we have:

\frac{n_{b} }{n_{a} } = sinθ_{a}/sinθ_{b}

In the given problem, we are given the refractive indices of light which are parallel and perpendicular to the axis of the optical lens as 1.4864 and 1.6584 respectively.

For critical angle θ_{a} = θ_{c}, θ_{b} = 90°; n_{b} = 1

(a) n_{a} = 1.4864

\frac{1 }{1.4864 } = sinθ_{c}/sin90°

0.6728 = sinθ_{c}θ[tex]_{c} = sin^(-1) 0.6728 = 42.28°(b) [tex]n_{a} = 1.6584

\frac{1 }{1.6584} = sinθ_{c}/sin90°

0.60299 = sinθ[tex]_{c}

θ[tex]_{c} = sin^(-1) 0.60299 = 37.08°

7 0
4 years ago
3 m/s
zloy xaker [14]

Answer:

0.75Hz

Explanation:

Given parameters:

Speed of the wave = 3m/s

Wavelength  = 4m

Unknown:

Frequency of the wave  = ?

Solution:

The speed of a wave is given by the expression below:

     Speed  = frequency x wavelength

  Frequency  = \frac{Speed }{Wavelength}   = \frac{3}{4}    = 0.75Hz

5 0
3 years ago
Conduction, convection, and radiation are ways by which,
Amiraneli [1.4K]

the answer is THERMAL

6 0
3 years ago
Read 2 more answers
An object carries a +15.5 uC charge.
abruzzese [7]

Answer:

3.67 N

Explanation:

From the question given above, the following data were obtained:

Charge of 1st object (q₁) = +15.5 μC

Charge of 2nd object (q₂) = –7.25 μC

Distance apart (r) = 0.525 m

Force (F) =?

Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:

For the 1st object

1 μC = 1×10¯⁶ C

Therefore,

15.5 μC = 15.5 × 1×10¯⁶

15.5 μC = 15.5×10¯⁶ C

For the 2nd object:

1 μC = 1×10¯⁶ C

Therefore,

–7.25 μC = –7.25 × 1×10¯⁶

–7.25 μC = –7.25×10¯⁶ C

Finally, we shall determine the force. This can be obtained as follow:

Charge of 1st object (q₁) = +15.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.25×10¯⁶ C

Distance apart (r) = 0.525 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²

F = 3.67 N

Therefore, the force on the object is 3.67 N

4 0
3 years ago
A 1.0 kg cart moving right at 5.0 m/s on a frictionless track collides with a second cart moving at 2.0m/s. The 1.0 kg cart has
____ [38]

Answer:

m₂ = 3kg

Explanation:

The question wasn't clear about what direction the initial velocity of the second cart was, so I'll assume it was going left at 2.0m/s.

Anyway, this is a conservation of momentum problem. The equation you need to use is the one written in blue. They want you to solve for the mass of the second cart, so do some algebra and rearrange that blue equation in term of m₂.

Now that you have the equation for m₂, plug in all the values given from the question and you'll get 3kg.

3 0
4 years ago
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