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Effectus [21]
3 years ago
12

20% Part (a) Use an "E Field Sensor" and move it along either equipotential. What can you say about the E field along an equipot

ential?
a. Varies in magnitude and direction, parallel to the equipotential.
b. Constant magnitude, but varying direction, perpendicular to the equipotential.
c. Varies in magnitude and direction, perpendicular to the equipotential.
d. Constant direction, but varying magnitude, perpendicular to the equipotential.
e. Constant direction, but varying magnitude, parallel to the equipotential.
f. Constant magnitude, but varying direction, parallel to the equipotential.
Physics
1 answer:
Alex3 years ago
6 0

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

\Delta E = -\frac{dV}{dr}

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

Then we will say

V = constant

so we have

\Delta E = 0

so electric field will remain constant always in magnitude and always remains perpendicular to the surface

so we have

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

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Answer:k=28.29 kN/m

Explanation:

Given

mass m =7700 kg

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thus From conservation of Energy Potential energy will convert in to Elastic Potential Energy of spring

\frac{kx^2}{2}=mg(h+x)----------1

also maximum acceleration is 5g

thus

mg-kx=ma

here a=-5g

kx=mg-m(-5g)=6mg

x=\frac{6mg}{k}

Substitute x in equation 1

0.5\times k\times (\frac{6mg}{k})^2=mg(h+\frac{6mg}{k})

18\frac{(mg)^2}{k}=mgh+6\frac{(mg)^2}{k}

k=12\cdot \frac{mg}{h}

k=12\times \frac{7700\times 9.8}{32}

k=28.29 kN/m

4 0
3 years ago
Two people were pulling this thing with 560 Newton. Now they are using a rope with 50°. How much Newton would they need to pull
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Answer:

10 N

Explanation:

While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

MIGHT BE TOTALLY WRONG

4 0
3 years ago
What's the difference between electromagnetic waves and electromagnetic spectrum?
White raven [17]
The difference between the two is, well for one

Spectrum: The entire range that the "<em>waves" </em>could be such, as visible light, x-ray's and so on.

Waves: These are different because they aren't telling you or showing the entire spectrum just which they length that they are.

<em>It may confuse you but it makes sense to me (Sorry)</em>
4 0
3 years ago
A dog of mass 18 kg runs at a speed of 4 m/s. What is the momentum of the
Andrej [43]

Answer:

A, 72 kg•m/s

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6 0
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a volleyball is hit upward with an initial velocity of 7.5 m/s. calculate the displacement of the volleyball when its final velo
Luden [163]

Answer:

The displacement of the volleyball is 2.62 m

Explanation:

Given;

initial velocity of the volleyball, u = 7.5 m/s

final velocity of the volleyball, v = 2.2 m/s

displacement of the volleyball, d = ?

Apply the following kinematic equation;

v² = u² - 2gd

2gd = u² - v²

d = \frac{u^{2}-v^{2}  }{2g}\\\\d = \frac{7.5^{2}-2.2^{2}  }{2*9.8}\\\\d = 2.62 \ m

Therefore, the displacement of the volleyball is 2.62 m

7 0
3 years ago
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