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Lady_Fox [76]
4 years ago
15

Susan bought 3 binders and 2 packages of paper for $13.35. . Dante bought 2 binders and 4 packages of paper for $17.30. How much

did each binder cost?
Mathematics
1 answer:
djverab [1.8K]4 years ago
0 0
It cost 4:05 just subtract and it will be that
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Box A has a volume of 12 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were multiplied by five. W
postnew [5]
Volume of B is 125×12=1500
4 0
3 years ago
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Amanda has $75 in her savings accountwhile Julie has $30 in her savings account Amanda adds $5 per week into her allowance and J
ELEN [110]

Answer:

$100

Step-by-step explanation:

Every week Amanda adds $5 and every week Julia adds $14. So all you have ti do is add $5 to Amanda's account and $14 to Julia's account until you have the same amount of money for the both of them.

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3 years ago
La cantidad requerida de un producto es de 100 unidades, cuando el precio es de $58 por unidad, y de 200 unidades, cuando el pre
Jobisdone [24]

Answer:

La expresión lineal es; 7y = 6500 - 100x

Step-by-step explanation:

Necesitamos entender que todos los modelos lineales siguen u obedecen la ecuación de una línea recta.

Matemáticamente, la ecuación de una línea recta se puede representar como;

y = mx + c

donde m representa la pendiente de la línea yc representa la intersección en y de la línea.

Para responder adecuadamente a esta pregunta, podemos ver que tenemos dos puntos de trama diferentes. Podemos visualizar nuestro modelo como una gráfica lineal del número de unidades contra el precio. Donde el número de unidades está en el eje y, y el precio está en el eje x.

Verifique el archivo adjunto para ver un diagrama de cómo debe verse la trama.

Ahora, calculemos la pendiente de nuestra línea que tiene 2 puntos en la línea;

(58,100) y (51,200)

Para calcular la pendiente m, podemos usar la relación matemática de la siguiente manera;

m = (y2-y1) / (x2-x1) = (200-100) / (51-58) = -100/7

Ahora tenemos la pendiente pero no tenemos la intersección en y.

Para obtener la intersección con el eje y, utilizamos cualquiera de los dos puntos de datos.

Usaré el segundo;

La ecuación de la línea en ese punto será;

200 = -100 / 7 (51) + c

 Tenemos;

7c = 1400 + 5100

7c = 6500

c = 6500/7

Ahora completemos nuestro modelo lineal ya que ahora tenemos la pendiente y la intersección en y

y = - (100/7) x + 6500/7

7 años = -100x + 6500

o simplemente 7y = 6500-100x

5 0
3 years ago
What is the product?
RSB [31]

Answer:

15a^5b^15

Step-by-step explanation:

you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.

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3 years ago
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If the data is spread out evenly, the measure of the center that is best to use is the what.
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That would be the mean.

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