The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :
Carbon-12 has the following electron configuration: 1s2-2s2-2p2. As seen in the configuration, the right answer is: the first electron shell has 4 orbitals.
The noble gas is Xenon and its molar mass is 131 g/mol.
<h3>What is the molar mass of the noble gas?</h3>
The molar mass of the noble gas is determined as follows;
Let molar mass of unknown gas be M, and mass of gas be m
Density of the noble gas, ρ = 5.8 g/dm³
density = m/V
At STP;
- temperature, T = 273.15 K
- pressure, P = 1 atm
- molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹
From ideal gas equation:
PV = nRT
where n = m/M
PV = mRT/M
M = mRT/PV
M = 0.0821 * 273.15 * 5.84/1
Molar mass of the noble gas = 131 g/mol
The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.
Learn more about molar mass at: brainly.com/question/837939
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