Answer:
Explanation:
The balanced equation is
I₂(g) + Br₂(g) ⇌ 2IBr(g)
Data:
Kc = 8.50 × 10⁻³
n(IBr) = 0.0600 mol
V = 1.0 L
1. Calculate [IBr]
![\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}](https://tex.z-dn.net/?f=%5Ctext%7B%5BIBr%5D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B0.0600%20mol%7D%7D%7B%5Ctext%7B1.0%20L%7D%7D%20%3D%20%5Ctext%7B0.0600%20mol%2FL%7D)
2. Set up an ICE table.
3. Calculate [I₂]
![\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DK_%7B%5Ctext%7Bc%7D%7D%26%3D%26%5Cdfrac%7B%5Ctext%7B%5BIBr%5D%7D%5E%7B2%7D%7D%20%7B%5Ctext%7B%5BI%24_%7B2%7D%24%5D%5BBr%5D%24_%7B2%7D%24%7D%7D%5C%5C%5C%5C8.50%20%5Ctimes%2010%5E%7B-2%7D%26%3D%26%7B%5Cdfrac%7B%280.0600%20-%202x%29%5E%7B2%7D%7D%7Bx%5E%7B2%7D%7D%7D%26%20%26%5C%5C%5C%5C0.2915x%20%26%20%3D%20%26%7B%5Cdfrac%7B0.0600%20-%202x%7D%7Bx%7D%7D%26%20%26%5C%5C%5C%5C0.2915x%20%26%20%3D%20%260.0600%20-%202x%5C%5C%5C%5C2.2915x%20%26%20%3D%20%26%200.0600%5C%5Cx%20%26%20%3D%20%26%20%5Ctextbf%7B0.026%2018%20mol%2FL%7D%5C%5C%5Cend%7Barray%7D%5C%5C)
4. Convert the temperature to kelvins
T = (150 + 273.15) K = 423.15 K
5. Calculate p(I₂)
Magnifying Glasses, Telescopes and Glasses.
Answer:
Francium (Fr)
Explanation:
Looking at the periodic table, Francium has 7 energy levels as it is in the 7th Period and is in the 1st Group (meaning it has one electron in the outermost shell) which suggests that it has one valence electron.
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