Answer:
1.346 v
Explanation:
1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:
(oxidation) 
→
E°=0.337 v
(reduction) 
→
E°=1.679 v
(overall) 
+8H^{+}_{(aq)}→
E°=1.342 v
2) Nernst Equation
Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:
![E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}](https://tex.z-dn.net/?f=E%3DE%5E%7B0%7D%20-%5Cfrac%7BRT%7D%7BnF%7DLn%5Cfrac%7B%5Bred%5D%7D%7B%5Box%5D%7D)
Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.
The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give
![E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346](https://tex.z-dn.net/?f=E%3D1.342%20-%5Cfrac%7B298.15%2A8.314%7D%7B6%2A96500%7DLn%5Cfrac%7B%5B.66%5D%7D%7B%5B1.69%5D%7D%3D1.346)
E=1.346
<span>Cr3+ O2- ; the formula is Cr2O3 ( criss cross)</span>
Its <span>c.chromatography is the process of separating solutions on the basis of their boiling points </span>
To determine the relative atomic mass of thallium, we multiply the molar mass of the isotopes to their corresponding relative abundance. The molecular percentages should sum up to 1. In this case, we multiply 203 by 0.295 and 205 by 0.705 and add the answers of the two. The final atomic mass is 204.41 g/mol.
Answer:
6.72 g
Explanation:
Given data:
Mass of calcium chlorate = 13.8 g
Mass of oxygen produced = ?
Solution:
Chemical equation:
Ca(ClO₃)₂ → CaCl₂ + 3O₂
Number of moles of calcium chlorate:
Number of moles = mass / molar mass
Number of moles = 13.8 g/ 206.98 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of oxygen and calcium chlorate.
Ca(ClO₃)₂ : O₂
1 : 3
0.07 : 3×0.07=0.21 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.21 mol × 32 g/mol
Mass = 6.72 g
