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hjlf
3 years ago
8

Where does the year go in a bar graph

Chemistry
1 answer:
Pani-rosa [81]3 years ago
7 0
The x axis. This is because the numbers go on the side so the years have to go on the bottem
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How many moles of H, O can be formed from 3.02 x 1023 atoms of NH from the
Yanka [14]

Answer:

Hey, I don't know but try 10+ (h) + 5 ), 79

6 0
3 years ago
Which of the following describes the location and energy of all the valence electrons
Nastasia [14]

Answer:

1s22s22p6<u>3s23p4</u>

Explanation:

Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)

4 0
3 years ago
Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is
Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal =  C_{134}H_{96}O_{9}NS

Molecular mass of coal = (134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm

Let’s calculate the mass of nitrogen in coal

Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}

Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = 4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0
3 years ago
Read 2 more answers
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
3 years ago
Sodium (Na) has 11 protons and 12 neutrons. What is its isotope notation?
DedPeter [7]

Answer:

Na ²³

ndnxnxnxnxnxnxnxnxn

7 0
4 years ago
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