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3 years ago

Where does the year go in a bar graph

Chemistry

1 answer:

Pani-rosa [81]3 years ago

7 0

The x axis. This is because the numbers go on the side so the years have to go on the bottem

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How many moles of H, O can be formed from 3.02 x 1023 atoms of NH from the

Yanka [14]

Answer:

Hey, I don't know but try 10+ (h) + 5 ), 79

6 0

3 years ago

Which of the following describes the location and energy of all the valence electrons

Nastasia [14]

Answer:

1s22s22p6<u>3s23p4</u>

Explanation:

Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)

4 0

3 years ago

Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is

Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal = $C_{134}H_{96}O_{9}NS$

Molecular mass of coal = $(134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm$

Let’s calculate the mass of nitrogen in coal

$Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}$

$Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%$

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = $4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons$

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0

3 years ago

Read 2 more answers

The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

3 years ago

Sodium (Na) has 11 protons and 12 neutrons. What is its isotope notation?

DedPeter [7]

Answer:

Na ²³

ndnxnxnxnxnxnxnxnxn

7 0

4 years ago