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m_a_m_a [10]
3 years ago
7

Find the net force and acceleration. 10 points. Will give brainliest.

Physics
2 answers:
Svetllana [295]3 years ago
5 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the FRICTION.

Force by Xavier = 25 N

Force of friction in the opposite direction of Xavier = f = umg

where, u = coefficient of kinetic friction.

so we here get as ,

Net force = 16 N

and acceleration = 2.13 m/s^2

Afina-wow [57]3 years ago
3 0

Answer:

a) 16 N

b) 2.13 m/s²

Explanation:

Draw a free body diagram of the tv stand.  There are four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

and applied force P pulling right.

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

The net force in the x direction is:

∑F = P − Nμ

∑F = P − mgμ

∑F = 25 N − (7.5 kg) (10 m/s²) (0.12)

∑F = 16 N

Net force equals mass times acceleration:

∑F = ma

16 N = (7.5 kg) a

a = 2.13 m/s²

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Answer:

8.19m

Explanation:

Parameters given:

Pressure, P= 11.6 psi = 79979.185 Pa

Gauge pressure is given as:

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2 years ago
A 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. The
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let the length of the beam be "L"

from the diagram

AD = length of beam = L

AC = CD = AD/2 = L/2

BC = AC - AB = (L/2) - 1.10

BD = AD - AB = L - 1.10

m = mass of beam = 20 kg

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m₂ = mass of child on right end = 40 kg

using equilibrium of torque about B

(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)

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algol [13]

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the answer for that is "A"

6 0
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You run away from a plane mirror at 2.30 m/s. At what speed does your image move away from you?
ivanzaharov [21]

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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len
worty [1.4K]

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