The apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ?
1 answer:
You might be interested in
Explanation:
Mass of bumper cars,
Initial speed of car A,
Initial speed of car Z,
Final speed of car A after the collision,
We need to find the velocity of car Z after the collision. Let it is equal to . Using the conservation of momentum as :
So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.
Answer:
a) 567J
b) 283.5J
c)850.5J
Explanation:
The expression for the translational kinetic energy is,
Substitute,
14kg for m
9m/s for v
The translational kinetic energy of the center of mass is 567J
(B)
The expression for the rotational kinetic energy is,
The expression for the moment of inertia of the cylinder is,
The expression for angular velocity is,
substitute
1/2mr² for I
and vr for w
in equation for rotational kinetic energy as follows:
The rotational kinetic energy of the center of mass is 283.5J
(c)
The expression for the total energy is,
substitute 567J for E(r) and 283.5J for E(R)
The total energy of the cylinder is 850.5J