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4 years ago

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What is the resulting direction of a surface wave?

2 answers:

german4 years ago

7 0

surface wave is a wave that travels along the surface of a medium. The medium is the matter through which the wave travels. Ocean waves are the best-known examples of surface waves. They travel on the surface of the water between the ocean and the air.

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sweet-ann [11.9K]4 years ago

5 0

This question is incomplete. Here is the complete question:

What is the resulting direction of a surface wave

A: Opposite

B: Circular

C: Parallel

D: Perpendicular

Answer:

The correct answer is option B. Circular.

Explanation:

This question can sometimes be confusing. The fact is that the surface waves go perpendicular and parallel as well, which results in their direction becoming CIRCULAR.

These types of waves usually appear when an earthquake occurs near the Earth's surface, and they move on this surface.

One of the types of surface waves is ocean waves. These waves move in a circular way.

To see how their movement is, you can search an internet search engine for a gif of “surface waves” and you can better understand this explanation.

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A 0.40 kg ball is suspended from a spring with spring constant 12 n/m . part a if the ball is pulled down 0.20 m from the equili

PolarNik [594]

The total mechanical energy of the system at any time t is the sum of the kinetic energy of motion of the ball and the elastic potential energy stored in the spring:
$E=K+U= \frac{1}{2}mv^2+ \frac{1}{2}kx^2$
where m is the mass of the ball, v its speed, k the spring constant and x the displacement of the spring with respect its rest position.

Since it is a harmonic motion, kinetic energy is continuously converted into elastic potential energy and vice-versa.

When the spring is at its maximum displacement, the elastic potential energy is maximum (because the displacement x is maximum) while the kinetic energy is zero (because the velocity of the ball is zero), so in this situation we have:
$E=U_{max}= \frac{1}{2}k(x_{max})^2$

Instead, when the spring crosses its rest position, the elastic potential energy is zero (because x=0) and therefore the kinetic energy is at maximum (and so, the ball is at its maximum speed):
$E=K_{max}= \frac{1}{2}m(v_{max})^2$

Since the total energy E is always conserved, the maximum elastic potential energy should be equal to the maximum kinetic energy, and so we can find the value of the maximum speed of the ball:
$U_{max}=K_{max}$
$\frac{1}{2}k(x_{max})^2 = \frac{1}{2}m(v_{max})^2$
$v_{max}= \sqrt{ \frac{k x_{max}^2}{m} }= \sqrt{ \frac{(12 N/m)(0.20 m)^2}{0.4 kg} }=1.1 m/s$

3 0

3 years ago

Olivia is on a swing at the playground.

balu736 [363]

Olivia is on a swing at the playground. The kinetic energy is increasing and her potential energy decreasing at point X.

<h3>What is kinetic energy and potential energy?</h3>

The kinetic energy of an object is the ability to do work by virtue of its motion and potential energy is the ability to do work by virtue of its position.

At point W and Z, Olivia is at the maximum displacement from the mean position, where kinetic energy is zero and potential energy is maximum.

At point Y, it is approaching to increase its potential energy and decreasing kinetic energy. Opposite to this, at point X, kinetic energy is increasing and potential energy is decreasing.

Thus, the kinetic energy is increasing and her potential energy decreasing at point X.

Learn more about kinetic energy and potential energy.

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5 0

3 years ago

Use this media to help you complete the question.

Papessa [141]

Answer:

589.3 g is the answer

Explanation:

6 0

3 years ago

A kicker punts a football from the very center of the field to the side line 37 yards down field. What is the displacement of th

Bas_tet [7]

The displacement would be the final position (37) minus the initial position (50) if using the displacement formula.

7 0

4 years ago

Read 2 more answers

A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei

Alenkinab [10]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

$F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\$

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

$F = (150\ N)Sin\ 20^o$

<u>F = 51.3°</u>

8 0

3 years ago