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zhannawk [14.2K]
3 years ago
7

If temperature increases, then pressure __________.

Physics
1 answer:
lilavasa [31]3 years ago
6 0
If the temperature increases, then pressure increases too. (T<span>he molecules in the gas move faster, exerting a greater force. This </span>increases t<span>he </span>pressure<span>.)</span>
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A girl travels 50m in 12s and then another 30m in 5s .Calculate her average speed?​
Zanzabum

Answer:

4.71m/s

Explanation:

Average speed = Total distance travelled ÷ Total time taken.

80/17=4.71

4.71m/s

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3 years ago
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What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?
riadik2000 [5.3K]

0.5 would be your answer >:o)

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4 years ago
How does food affects carbon footprint?
eduard

Answer:

Food accounts for 10-30% of a household's carbon footprint, typically a higher portion in lower-income households. Production accounts for 68% of food emissions, while transportation accounts for 5%.

Explanation:

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3 years ago
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You have been abducted by aliens and find yourself on a strange planet. Fortunately, you have a meter stick with you. You observ
defon

Answer:

36.4276\ m/s^2

Explanation:

m = Mass of stick

L = Length of stick = 1 m

h = Center of mass of stick = \dfrac{1}{2}=0.5\ m

g = Acceleration due to gravity

T = Time period = 0.85 s

Time period is given by

T=2\pi\sqrt{\dfrac{I}{mgh}}

Moment of inertia is given by

I=m\dfrac{L^2}{3}

T=2\pi\sqrt{\dfrac{m\dfrac{L^2}{3}}{mgh}}\\\Rightarrow T=2\pi\sqrt{\dfrac{L^2}{3gh}}\\\Rightarrow g=\dfrac{4\pi^2L^2}{3hT^2}\\\Rightarrow g=\dfrac{4\pi^2\times 1^2}{3\times 0.5\times 0.85^2}\\\Rightarrow g=36.4276\ m/s^2

The acceleration of gravity on this planet is 36.4276\ m/s^2

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3 years ago
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A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

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3 years ago
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