Your answer would be 5.572 x 10 squared
Answer:
v₀ = 14.6 m / s
Explanation:
This is a projectile launch exercise, in this case we must stop the wall, we can assume that at this point the ball is at its maximum height
as the height is maximum its vertical speed is zero
v_{y} = - g t
y = v_{oy} t - ½ g t²
the horizontal distance is
x = v₀ₓ t
we use trigonometry to find the components of the velocity
sin θ = v_{oy} / v₀
cos θ = v₀ₓ / v₀
v₀ₓ = v₀ cos θ
v_{oy} = v_{o} sin θ
we substitute the values
0 = v₀ sin θ - g t
10 = v₀ sin θ t - ½ g t²
6 = v₀ cos θ t
we have three equations and three unknowns by which the system can be solved
let's use the first and second equations,
10 = (gt) t - ½ g t²
10 = g t² - ½ g t²
10 / 9.8 = t² (1- ½)
1.02 = ½ t²
t = √ 2.04
t = 1,429 s
this is the time to hit the wall
now let's use the first and third equations, we substitute the data
v₀ sin θ = g t
v₀ cos θ = x / t
we divide and simplify
tan θ = g t² / x
θ = tan⁻¹ g t² / x
θ = tan⁻¹ (9.8 1.429²/6)
θ = 73.3°
we substitute in the third equation
x = v₀ cos 73.3 t
v₀ = x / t cos 73.3
v₀ = 6 / (1.429 cos 73.3)
v₀ = 14.6 m / s
Answer:
Potential energy can transfer into other forms of energy like kinetic energy. Kinetic energy is energy an object has because of its motion. ... If released, as the ball moves faster and faster toward the ground, the force of gravity will transfer the potential energy to kinetic energy.
On a microscopic scale, conduction occurs as rapidly moving or vibrating atoms and molecules interact with neighboring particles, transferring some of their kinetic energy. Heat is transferred by conduction when adjacent atoms vibrate against one another, or as electrons move from one atom to another.
Answer:
The intensity of the light that passes through a polarizer is 0.55I₀.
Explanation:
The intensity of the light that passes through a polarizer can be found using Malus's law:
<u>Where</u>:
I: is the intensity of the light that passes through a polarizer
I₀: is the initial intensity
θ: is the angle between the light's initial polarization direction and the axis of the polarizer = 42°
Therefore, the intensity of the light that passes through a polarizer is 0.55I₀.
I hope it helps you!