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Burka [1]
2 years ago
11

1. The law of reflection states that the angle of _______ is equal to the angle ofreflection

Physics
1 answer:
Mnenie [13.5K]2 years ago
3 0

Answer:

refraction

Explanation:

but this is easy so why

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The work done by the brakes during braking is equal to
kow [346]

Answer:

The amount of pressure delivered to them

Explanation:

6 0
2 years ago
An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionles
Arada [10]

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

7 0
1 year ago
A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelera
user100 [1]

Answer:

Vf₁ = 30 m/s

s₂ = 90 m

car wins the race.

Explanation:

To find the speed of car after 5 s, we use 1st equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car = ?

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 5 m/s²

t₁ = time = 5 s

Therefore,

Vf₁ = 0 m/s + (5 m/s²)(5 s)

<u>Vf₁ = 25 m/s</u>

<u></u>

To find the distance of motorcycle after 6 s, we use 2nd equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered by the motorcycle = ?

Vi₁ = Initial Speed of motorcycle = 0 m/s

a₂ = acceleration of motorcycle = 8 m/s²

t₂ = time = 6 s

Therefore,

s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²

<u>s₂ = 90 m</u>

<u></u>

We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:

For Car:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)

Therefore.

150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²

t₁ = √60 s²

t₁ = 7.74 s

For Motorcycle:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₁ = 200 m

Therefore.

200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²

t₂ = √80 s²

t₂ = 8.94 s

Since, the car takes less time to reach finish line.

Therefore, car wins the race.

5 0
3 years ago
The increases in a planet's speed as it approaches the sun is described by kepler's second law what is the best explanation for
Keith_Richards [23]
<span>Keplers second law, that gravitational potential energy is lost when planets get near the sun and it becomes kinetic energy, best describes the reason why a planets speed will increase as it becomes closer to the sun.</span>
5 0
3 years ago
An astronaut is being tested in a centrifuge. The centrifuge has a radius of 11.0 m and, in starting, rotates according to θ = 0
maxonik [38]

Answer:

ω = 2.9 rad/s, v = 31.7 m/s, α = 0.78 rad/s², a = 91,6 m/s²

Explanation:

I will assume the given equation reads as Ф = 0.39t².

The angular velocity ω is the time derivative of Ф.

ω = 0.78t

The linear velocity v is given by ωr, where r is the radius of the centrifuge.

v = 0.78t r

The tangential acceleration α is the time derivative of ω.

α = 0.78

The radial acceleration a is given by: a = ω²r

a = (0.78t)²r

8 0
3 years ago
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