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Burka [1]
3 years ago
11

1. The law of reflection states that the angle of _______ is equal to the angle ofreflection

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

refraction

Explanation:

but this is easy so why

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Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as sh
puteri [66]

Answer:

F = 19.1 N

Explanation:

To find the force exerted by the string on the block you use the following formula:

F=kx  (1)  

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

F=(95.5N/m)(0.200m)=19.1N

Hence, the force exterted on the block is 19.1 N

 

8 0
3 years ago
A closed system consisting of 2 lb of a gas undergoes a process during which the relation between pressure and volume is pVn = c
vazorg [7]

Answer:

V1=<u>2.5ft3</u>

<u>V2=1ft3</u>

n=1.51

Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

V=mv

state 1

V1=m.v1

V1=2lb*1.25ft3/lb=<u>2.5ft3</u>

state 2

V2=m.v2

V2=2lb*0.5ft3/lb=  <u> 1ft3</u>

PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

P1V1^n=P2V2^n

P1/P2=(V2/V1)^n

ln(P1/P2)=n . ln (V2/V1)

n=ln(P1/P2)/ ln (V2/V1)

n=ln(15/60)/ ln (1/2.5)

n=1.51

8 0
3 years ago
What is the thermal energy of an object?
nalin [4]
The answer would be A!
6 0
3 years ago
Read 2 more answers
What is the slope of the line plotted below?<br> A. 1.33<br> B. -1.33<br> C. -0.6<br> D. 0.6
Naya [18.7K]

Answer:

C. -0.6

Explanation:

Line is passing through the points ( - 3, 1) & (2, - 2)

Slope of line

=  \frac{ - 2 - 1}{2 - ( - 3)}  =  \frac{ - 3}{2 + 3}  =  \frac{ - 3}{5}  =  - 0.6 \\

4 0
3 years ago
wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate
liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates6.00\times 10^{-3} m^2

distance between the plates is 1.50\times 10^{-4} m

charge = 5.40\times 10^{-8} c

we know that capacitance is given as

C = \frac{\epsilon A}{d}

C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}

C = 3.54\times 10^{-10} F

potential difference is given as

V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}

V = 152.542 volts

3 0
3 years ago
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