The ammeter reading (current) will decrease.
V=IR
I = V/R
so I is inversely proportional to R, i.e. increasing R will cause I to decrease
Answer:
I = 0.75 A
Explanation:
The question is not to calculate the resistance, but to calculate the current. (The resistance is already given by the value of 2 Ohm).
U = I * R
I = U / R
with U = 1.5 V and R = 2 Ohm
I = 1.5 / 2
I = 0.75 A
Answer:
The right approach will be Option C "Group 12".
Explanation:
- A table that further arranges the chemical components in addition to expanding the electron configuration. Elements possessing identical characteristics are positioned in almost the same section (column or group), although elements in almost the same row become positioned with a similar amount of electron spheres.
- Group 12 components therefore partially replaced (n − 1)d subshells, and therefore aren't metals, technically accurate. However, although much their chemistry seems to be comparable to something like the components throughout the d block which includes establishing themselves.
Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.
The answer would be erin out of all of them thank me later :)
Answer:
ΔU = - 9,179 10-11 J
Explanation:
For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy
U = - G m₁m₂ / R
In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m
U₁ = - G m² / r₁
let's calculate
U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19
U₁ = - 10,619 10⁻¹¹ J
when its centers are separated it is at r₂ = 1.4 m
U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4
U₂ = - 1.44 10-11 J
the energy between these two points is
ΔU = U₂ - U₁
ΔU = (-1.44 +10.619) 10-11
ΔU = - 9,179 10-11 J
