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Butoxors [25]
3 years ago
11

1. When playing the piano, each key has a specific number of times it vibrates. The number of string vibrations correspond to ch

anging what quality of sound? loudness
pitch
amplitude
range
2. What is the lowest level of sound that can be detected by human hearing?
0 Hz
10 Hz
20 Hz
100 Hz
3.

The sound waves used for sonar are _____.
infrasound
ultrasound
audible
4. At close range, a ship's foghorn or the air horn on a truck will probably have a ______(High, Low, Medium) decibel reading.
5. A loud explosion will produce _____.
a high-amplitude sound wave
a low-amplitude sound wave
a sound wave with a single frequency
Physics
2 answers:
kakasveta [241]3 years ago
3 0

Answer:

2: 20HZ 3:audiable

Explanation:

i guessed and it told me i was right

PilotLPTM [1.2K]3 years ago
3 0

Answer: Hello mate!

1) the number of times that the string vibrates ober the unit of time, is the frequency of the note.

This canges the pitch of the note, where a high frequency is asociated with a high pitch (the first string in the guitar) and a low frequency is asociated with a low pitch (the thickest string on a guitar)

2) Is commonly stated that the human hearing can detect sounds of 20Hz, but in some situations can be detected sounds with lower frequency, where the samallest detected is 12Hz

3) The sound waves used for a sonar can vary from infrasound to ultrasound, depending of the range that the sonar covers, there is no right answer here.

4) A high decibel reading, this is because the source "shots" the sound un a prefered direction, then the intensity of the sound is very high right next to the source.

5) A loud explosion will produce a high-amplitude sound wave, this is because the amplitud is directly relationated with the intensity (or loudnes) of the sound wave.

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A box rests on top of a flat bed truck. The box has a mass of m = 16.0 kg. The coefficient of static friction between the box an
3241004551 [841]

Answer:

1) 1.31 m/s2

2) 20.92 N

3) 8.53 m/s2

4) 1.76 m/s2

5) -8.53 m/s2

Explanation:

1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s

a = \frac{\Delta v}{\Delta t} = \frac{17 - 0}{13} = 1.31 m/s2

2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration

F_s = am = 1.31*16 = 20.92 N

3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.

F_{\mu_s} = \mu_sN = mg\mu_s = 16*9.81*0.87 = 136.6N

So the maximum acceleration on the block is

a_{max} = F_{\mu_s} / m = 136.6 / 16 = 8.53 m/s^2

4)As the box slides, it is now subjected to kinetic friction, which is

F_{\mu_s} = mg\mu_k = 16*9.81*0.69 = 108.3 N

So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is

28.25 / 16 = 1.76 m/s2

5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2

3 0
3 years ago
In an electron cloud, an electron farther east away from the nucleus has?
vladimir2022 [97]

An electron that is far away from the nucleus have higher energy than an electron near the nucleus. Nucleus are positively charged and those electrons near it get attracted; those electrons gain kinetic energy hence reducing their internal energy. The electrons far from nucleus have low kinetic energy hence more internal energy.

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3 years ago
A swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across a river that has a downstream curre
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3 years ago
Who’s of the following is classified as a salt: ammonia or sodium chloride?
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Sodium Chloride could be classified as a salt.

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3 years ago
The energy flow per unit time per unit area (S) of an electromagnetic wave has an average value of 310 mW/m2. The maximum value
Aleksandr-060686 [28]

Answer:

5.096*10^-8

Explanation:

Given that

The average value of the electromagnetic wave is 310 mW/m²

To find the maximum value of the magnetic field the wave is closest to, we say

Emax = √Erms

Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]

Emax = √233.7648

Emax = 15.289

Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer

15.289 / (3*10^8) = 5.096*10^-8 T

Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8

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