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Butoxors [25]
3 years ago
11

1. When playing the piano, each key has a specific number of times it vibrates. The number of string vibrations correspond to ch

anging what quality of sound? loudness
pitch
amplitude
range
2. What is the lowest level of sound that can be detected by human hearing?
0 Hz
10 Hz
20 Hz
100 Hz
3.

The sound waves used for sonar are _____.
infrasound
ultrasound
audible
4. At close range, a ship's foghorn or the air horn on a truck will probably have a ______(High, Low, Medium) decibel reading.
5. A loud explosion will produce _____.
a high-amplitude sound wave
a low-amplitude sound wave
a sound wave with a single frequency
Physics
2 answers:
kakasveta [241]3 years ago
3 0

Answer:

2: 20HZ 3:audiable

Explanation:

i guessed and it told me i was right

PilotLPTM [1.2K]3 years ago
3 0

Answer: Hello mate!

1) the number of times that the string vibrates ober the unit of time, is the frequency of the note.

This canges the pitch of the note, where a high frequency is asociated with a high pitch (the first string in the guitar) and a low frequency is asociated with a low pitch (the thickest string on a guitar)

2) Is commonly stated that the human hearing can detect sounds of 20Hz, but in some situations can be detected sounds with lower frequency, where the samallest detected is 12Hz

3) The sound waves used for a sonar can vary from infrasound to ultrasound, depending of the range that the sonar covers, there is no right answer here.

4) A high decibel reading, this is because the source "shots" the sound un a prefered direction, then the intensity of the sound is very high right next to the source.

5) A loud explosion will produce a high-amplitude sound wave, this is because the amplitud is directly relationated with the intensity (or loudnes) of the sound wave.

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Say the tortoise and the hare are racing. If the tortoise moves straight
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Explanation:

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You are hungry and decide to go to your favorite neighborhood fast-food restaurant. You leave your apartment and take the elevat
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Answer:

A)  R = (200 i ^ + 100 j ^ + 30k ^) m , B)    L = 223.61 m , C)   R = 225.61 m

Explanation:

Part A

This is a vector summing exercise, let's take a Reference System where the z axis corresponds to the height (flights), the x axis is the East - West and the y axis corresponds to the North - South.

Let's write the displacements

Descending from the apartment

10 flights of 3 m each, the total descent is 30 m

                Z = 30 k ^ m

Offset at street level

            L1 = 0.2 i ^ km

            L2 = 0.1 j ^ km

Let's reduce everything to the SI system

          L1 = 0.2 * 1000 = 200 i ^ m

          L2 = 100 j ^ m

The distance traveled is

          R = (200 i ^ + 100 j ^ + 30k ^) m

Part B

The horizontal distance traveled can be found with the Pythagorean theorem for the coordinates in the plane

                L² = x² + y²

                L = √ (200² + 100²)

                L = 223.61 m

Part C

The magnitude of travel, let's use the Pythagorean theorem for the sum

             R² = x² + y² + z²

              R = √ (30² + 200² + 100²)

             R = 225.61 m

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Answer:

volume

Explanation:

it depends on the volume of the items

hope this helps

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