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Butoxors [25]
3 years ago
11

1. When playing the piano, each key has a specific number of times it vibrates. The number of string vibrations correspond to ch

anging what quality of sound? loudness
pitch
amplitude
range
2. What is the lowest level of sound that can be detected by human hearing?
0 Hz
10 Hz
20 Hz
100 Hz
3.

The sound waves used for sonar are _____.
infrasound
ultrasound
audible
4. At close range, a ship's foghorn or the air horn on a truck will probably have a ______(High, Low, Medium) decibel reading.
5. A loud explosion will produce _____.
a high-amplitude sound wave
a low-amplitude sound wave
a sound wave with a single frequency
Physics
2 answers:
kakasveta [241]3 years ago
3 0

Answer:

2: 20HZ 3:audiable

Explanation:

i guessed and it told me i was right

PilotLPTM [1.2K]3 years ago
3 0

Answer: Hello mate!

1) the number of times that the string vibrates ober the unit of time, is the frequency of the note.

This canges the pitch of the note, where a high frequency is asociated with a high pitch (the first string in the guitar) and a low frequency is asociated with a low pitch (the thickest string on a guitar)

2) Is commonly stated that the human hearing can detect sounds of 20Hz, but in some situations can be detected sounds with lower frequency, where the samallest detected is 12Hz

3) The sound waves used for a sonar can vary from infrasound to ultrasound, depending of the range that the sonar covers, there is no right answer here.

4) A high decibel reading, this is because the source "shots" the sound un a prefered direction, then the intensity of the sound is very high right next to the source.

5) A loud explosion will produce a high-amplitude sound wave, this is because the amplitud is directly relationated with the intensity (or loudnes) of the sound wave.

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Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de
Vesnalui [34]

Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 \frac{m}{s}

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa.  Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido,  en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

  • A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.
  • v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4} , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2

En este caso:

  • D1: 0.06 m
  • v1: ?
  • D2: 0.04 m
  • v2: 2.6 m/s

Reemplazando:

\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}

Resolviendo:

v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}

v1=\frac{(0.04m)^{2} }{(0.06m)^{2}  }*2.6\frac{m}{s}

v1= 1.156 \frac{m}{s}

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u>\frac{m}{s}<u><em></em></u>

8 0
3 years ago
Which statement correctly explains molecular motion in different states of matter using the kinetic theory?
Gelneren [198K]

the answer is the second one

8 0
3 years ago
If a net force of 250 N causes an object to accelerate at 20m/s^2 what must its mass be?
aleksandr82 [10.1K]
The answer is 12.5 kg because 250N / 20m/s^2

I hope that helped
7 0
4 years ago
If you are driving your car at 45.0 miles per hour, and you have been driving 2.50 hours, how far has your car gone?
Greeley [361]

Answer:

113 miles

Explanation:

45.00 x 2.50= 1.12.5 so 113 miles in 2.50 hours

5 0
3 years ago
Which best defines nitrogen fixation? the process of creating free nitrogen for plants to absorb the breakdown of nitrogen in th
son4ous [18]

The nitrogen fixation is the process of conversion of nitrogen gas into a usable form.

Answer: Option 3

<u>Explanation: </u>

The nitrogen fixation is the process where the nitrogen gas present in air gets trapped and converted into ammonia or other nitrogenous compounds. This is the first step of nitrogen cycle.

The atmospheric nitrogen will get absorb in soil and gets converted to either ammonia which acts as nutrition for plants or other nitrogen related compounds which acts as fertilizers.

So, the nitrogen which get converted to usable stable form of nitrogen compounds can be used by plants, microorganisms and other organisms in the ecosystem.

7 0
3 years ago
Read 2 more answers
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