a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exer
ted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg
2 answers:
Answer:
-7500 N
Explanation:
v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
Answer:-7500
Explanation v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
You might be interested in
i do believe the answer is c not sure but correct me if im wrong
A textbook would hit the ground first
Factors:
-Textbook weighs most
-Pillow is flat and fluffy not very aerodynamic) also is very light
-Paper airplane will glide to the ground do to its wings and will hit the ground last
The answer is A.) 27<span />
Oxygen bc plants go through photosynthesis which keeps producing more oxygen
Answer:
mass = 0.18 [kg]
Explanation:
This is a classic problem where we can apply the definition of density which is equal to mass over volume.
![density = \frac{mass}{volume} \\\\where:\\volume = 1 [m^3]\\density = 0.18[kg/m^3]](https://tex.z-dn.net/?f=density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C%5C%5Cwhere%3A%5C%5Cvolume%20%3D%201%20%5Bm%5E3%5D%5C%5Cdensity%20%3D%200.18%5Bkg%2Fm%5E3%5D)
mass = 0.18*1
mass = 0.18 [kg]
