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alexandr402 [8]
3 years ago
6

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)

Physics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

B false

Explanation:

dont have any explanation

777dan777 [17]3 years ago
6 0

Answer:

b

Explanation:

you see when something is changing directions it is accelerating, not in a sence is speed is changing altho its volocity is (speed and direction)

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Refraction occurs because of changes in the _____________
IrinaVladis [17]
Speed of the beam as it passes from one transparent medium to another
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3 years ago
A 10-kilogram mass is sliding along a frictionless floor with an acceleration of 5 meters per second squared. What is the magnit
Darina [25.2K]

Answer:

50N

Explanation:

Since the floor is frictionless, the net force = mass × acceleration.

given that,

mass = 10kg

and acceleration is 5 m/s²

Thus,

Force = 10 × 5

Force = 50 N

5 0
3 years ago
Madison pushes with a 210-N horizontal force on a 24-kg crate of coffee resting on a warehouse floor. The force of friction on t
kotykmax [81]

Answer:

5.7 m/s^2

Explanation:

First of all, we need to calculate the resultant force on the crate. We have:

- A force of +210 N in the positive direction

- The frictional force of -74 N in the opposite direction

So, the resultant force is

F = 210 N - 74 N= 136 N

So now we can apply Newton's second law to find the acceleration:

F=ma

where m=24 kg is the mass of the crate. Re-arranging the equation, we get:

a=\frac{F}{m}=\frac{136 N}{24 kg}=5.7 m/s^2

5 0
3 years ago
If a car accelerates at an average rate of 7.92 m/s2. Calculate how long it takes the car to speed up from 6.38 m/s to 34.86 m/s
blondinia [14]

a = \dfrac{\Delta v}{\Delta t} \\~\\~\\a = \dfrac{v-v_0}{\Delta t} \\~\\~\\7.92 = \dfrac{34.86-6.38}{\Delta t} \\~\\~\\\Delta t = \dfrac{2848}{792} \\~\\~\\ \Delta t = 3+\dfrac{472}{792} \\~\\~\\\Delta t = 3+\dfrac{2^3\cdot(59)}{2^3\cdot(99)} \\~\\~\\\Delta t = 3 + 0.5959\cdots \\~\\~\\\Delta t \approx 3.6

It takes aproximately 3.6 secs

5 0
3 years ago
Read 2 more answers
A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . What is the electric force acting on the
arlik [135]

Answer:

0.9N/C

Explanation:

-The force of a charged particle in an electric field is given by the equation;

F=qE\\\\q-charge\\

#we substitute the values of the charge and field strength:

F=qE\\\\=4.5\times10^{-5}\times2.0\times10^4\\\\=0.9 \ N/C

Hence, the electric force acting on the charge is 0.9N/C

7 0
3 years ago
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