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Yuliya22 [10]
4 years ago
6

24. Use Newton’s first law of motion to explain how wearing a seat belt in a moving car would help prevent injury (3 points)

Physics
1 answer:
barxatty [35]4 years ago
6 0
Idk sorry not sorry
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A thin hoop is supported in a vertical plane by a nail. What should the radius of the hoop be in order for it to have a period o
maxonik [38]

Answer:

0.124 m

Explanation:

the period of a simple pendulum with a small amplitude is given as

T = 2π [√(I/mgd)]

From the above stated formula,

I = moment of inertia

m = mass of the pendulum

g = acceleration due to gravity, 9.8 m/s²

d = distance from rotation axis due to center of gravity

Also, moment of Inertia, I = 2mr², if we substitute this in the above formula, we have

T = 2π [√(2mr²/mgd)]

If we assume that our r = d, then we have

T = 2π [√(2r/g)]

If we make r the subject of the formula in the above equation, we get

r = gT² / 8π²

r = (9.8 * 1²) / 8 * π²

r = 9.8 / 78.98

r = 0.124 m

Thus, the radius of the hoop is 0.124 m

4 0
3 years ago
What are the charged particles called in thermoshpere?
ira [324]
They are called Ions 
Definition is this: atom of molecule with a net electric charge caused by the loss or gain of one or more electrons.
Hope this helps! :D
3 0
4 years ago
2. A person lifts 200kg seven times over the course of 11.8s. If they displaced the weight 2.2m up each time, how much power did
Aneli [31]

Answer:

<em>The person delivered a power of 2,558 Watt</em>

Explanation:

<u>Work and Power</u>

Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being  the force vector and  the displacement vector, the work is calculated as:

W=\vec F\cdot \vec s

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.

The power can be calculated as:

\displaystyle P=\frac {W}{t}

Where W is the work and t is the time.

If the person lifts a mass of m=200 Kg, then exerts a force equal to its weight:

F = m.g = 200*9.8 = 1,960

F = 1,960 N

The work done when lifting the weight 7 times by a distance of s=2.2 m is:

W = 7*1,960*2.2=30,184

W = 30,184 J

Finally, the power delivered in t=11.8 seconds is:

\displaystyle P=\frac {30,184}{11.8}

P = 2,558 Watt

The person delivered a power of 2,558 Watt

4 0
3 years ago
Light from a distant star is collected by a concave mirror that has a radius of curvature of 150 cm. How far from the mirror is
andrey2020 [161]
The focal point of a mirror is half of the radius of curvature. We can use the formula,                                                                                                                   1/f = 1/v + 1/u                                                                                                          where f is the focal length , v is the image distance and u is object distance        The distance of the star is assumed to be incredibly far away and 1 divided by a really big number is approximately zero, thus;                                                     1/f = 1/v  = 1/75 = 1/v                                                                                             therefore; the image is formed 75 cm infront of the mirror
4 0
4 years ago
Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart.
serious [3.7K]

Answer:

1.6\times 10^{-7} N

2.4\times 10^{-7} N

Explanation:

i_{1} = 1 A

i_{2} = 4 A

r = distance between the two wire = 5 m

F = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}

F = (10^{-7})\frac{2(1)(4)}{5}

F = 1.6\times 10^{-7} N

r'} = distance of each wire from the midpoint = 2.5 m

Magnetic field midway between the two wires is given as

B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))

B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))

B = 2.4\times 10^{-7}

5 0
3 years ago
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