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Nookie1986 [14]

3 years ago

13

A man pushes his lawnmower with a velocity of +0.75 m/s relative to the ground. A girl rides by on her bike with a velocity of +

6.5 m/s relative to the ground. What is the velocity of the girl relative to the lawnmower? A. 0 m/s B. +5.75 m/s C. +6.5 m/s D. +7.25 m/s

2 answers:

SashulF [63]3 years ago

8 0

Answer:

B. +5.75 m/s

Explanation:

When there are two bodies, a and b, whose velocities measured by a third observer (in this case, the ground) are $V_a$ and $V_b$ respectively, the relative velocity of B with respect to A is given by:

$V_{ba}=V_b-V_a$

Thus, the velocity of the girl relative to the lawnmower is:

$V_{ba}=6.5\frac{m}{s}-0.75\frac{m}{s}\\V_{ba}=5.75\frac{m}{s}$

ZanzabumX [31]3 years ago

4 0

I took the test and got B) +5.75 m/s correct

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