Answer:
rgvdghrryyrfgtr was the other monkey that I have to do with my best pet peeve for the rest and neon scooter is my friend is giving her the money for your cuz to be a good offer tho it was a great idea for a while and then she said yes and she is a great person ever and she was madly happy I have to go soon to be honest with me if she wants me back to my base or not but she wasnt it to be honest with her but
Answer:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
Explanation:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
When this alpha particles were made to strike the aluminum foil, some passed through the foil, some were reflected and speed others changed.
The ones reflected encountered heavier particle known as the nucleus, preventing them from passing through it. The whole observations indicated that atom is not is uniformly charged sphere as proposed by J.J Thomson.
Rutherford proposed new model known as the Planetary model of atom, which described atom as containing a nucleus which is revolved by electron, just like planets revolve round the sun. And this nucleus contains opposite charge to electron which is proton, to balance the motion.
There are several different types of spectrums that you could expect to find from
the gas cloud, but the best option from the list would be "<span>high-frequency spectrum".</span>
Answer:
<h2>line B</h2>
Explanation:
According to ohm's law V = IR where;
V i sthe supply voltage (in volts)
I = supply current (in amperes)
R = resistance (in ohms)
In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.
For line B, R = ΔV/ΔI
R = V₂-V₁/I₂-I₁
R = 14.0-4.0/7.0-2.0
R = 10.0/5.0
R = 2.0ohms
Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.
Answer:
<h2>a) Time elapsed before the bullet hits the ground is 0.553 seconds.</h2><h2>b)
The bullet travels horizontally 110.6 m</h2>
Explanation:
a) Consider the vertical motion of bullet
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 1.5 m
Substituting
s = ut + 0.5 at²
1.5 = 0 x t + 0.5 x 9.81 xt²
t = 0.553 s
Time elapsed before the bullet hits the ground is 0.553 seconds.
b) Consider the horizontal motion of bullet
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 200 m/s
Acceleration, a = 0 m/s²
Time, t = 0.553 s
Substituting
s = ut + 0.5 at²
s = 200 x 0.553 + 0.5 x 0 x 0.553²
s = 110.6 m
The bullet travels horizontally 110.6 m
