What is the power of a light bulb that has a resistance of 190 ohms in a 120 v circuit?
2 answers:
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Answer:
f = 8 N
Explanation:
Data provided in the question
Radius of the pulley = r = 0.05 m
Moment of inertia = (I) = 0.2 kg.m^{2}
Angular acceleration = ∝ = 2 rad/sec
Based on the above information
As we know that
Torque is
And,
Torque is also
So,
We can say that
0.05f = 0.4
f = 8 N
We simply applied the above formulas