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Leno4ka [110]
3 years ago
10

When 1kg of a substance changes from solid to liquid at its melting point, it must absorbed an amount of heat equal to which of

the following?
A. specific heat of phase changes
B. specific heat capacity
C. latent heat of fusion
D. latent heat of vaporization
Physics
1 answer:
quester [9]3 years ago
4 0
Answer is (c), the latent heat of fusion. That is by definition the heat that 1 kg of a substance must absorb to melt in the vicinity of its melting point.
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How much heat is released when 35kg of water freezes?
inn [45]
You need an additional point of data here: the enthalpy of fusion, or conversely the enthalpy of melting (they differ only by their sign). For water (or ice) that value is gotten from sources such as the internet

<span>ΔH°(fus) = 6.01 kJ/mole </span>

<span>Since you have 35 000g, how many moles do you have? </span>
<span>Moles H2O = 35000 g/(18.015 g/mole) = 1942.8 moles</span>

<span>So, take that ΔH°(fus) in kJ/mole, multiply by the number of moles, and there ya go! 
</span>
6.01 x 1942.8 = 11,676 kJ of energy is released

Hope I helped!! xx
3 0
3 years ago
What is the momentum of a 0.16-kg apple that moves with a speed of 2.7m/s
Ksju [112]

Answer: 0.432kgm/s

Explanation:

Momentum of a body is defined as the product of the mass (m) of the body and its velocity (v).

Momentum = Mass × Velocity

Given mass = 0.16kg and velocity = 2.7m/s

Substituting the datas into the formula,

Momentum = 0.16×2.7

Momentum = 0.432kgm/s

8 0
3 years ago
Read 2 more answers
A 23 kg suitcase is being pulled with a constant speed by a handle that is at an angle of 29° above the horizontal. If the norma
Zina [86]

<u>Answer:</u>

The force F applied to the handle = 330.03 N

<u>Explanation:</u>

    The force can be resolved in to two, horizontal component and vertical component. If θ is the angle between horizontal and applied force we have

     Horizontal component of force = F cos θ

    Vertical component of force = F sin θ

  In this problem normal force exerted on the suitcase is 160 N, that is  vertical component of force = 160 N and angle θ = 29⁰.

 So, F sin 29 = 160

        F = 330.03 N

 The force F applied to the handle = 330.03 N

6 0
3 years ago
Read 2 more answers
How does the total momentum of the docked vehicle and station compare to the momentum of each object before the
Xelga [282]

The total momentum before the docking maneuver is  and after the docking maneuver is

Explanation:

Linear momentum  (generally just called momentum) is defined as mass in motion and is given by the following equation:  

 

Where  is the mass of the object and  its velocity.

According to the conservation of momentum law:

"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision  will be the same as the total momentum of these same two objects after the collision ".

This means, that although the momentum of each object may change after the collision, the total momentum of the system does not change.

Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

Hence, the initial momentum is:

Where:

is the mass of the vehicle

is the velocity of th vehicle

is the mass of the space station

is the velocity of the space station

And the final momentum is:

Where:

is the velocity of the vehicle and space station docked

5 0
4 years ago
The reason a charged balloon will stick to a wall is that?
kari74 [83]
The negative charges of the balloon will stick to the positive charges on the wall.
6 0
3 years ago
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