Answer:
Power output = 96.506 watts
Explanation:
Drag coefficient (Cd) = 0.9
V = 7.3 m/s
Air density (ρ) = 1.225 kg/m^(3)
Area (A) = 0.45 m^2
Let's find the drag force ;
Fd=(1/2)(Cd)(ρ)(A)(v^(2))
So Fd = (1/2)(0.9)(1.225)(0.45)(7.3^(2)) = 13.22N
Drag power = Drag Force x Drag velocity.
Thus drag power, = 13.22 x 7.3 = 96.506 watts
Answer:
Explanation:what’s the answer ?
Answer:
D=387.28m
Explanation:
At the moment where the toss is made
, so we need both equations:
For the red car:
With initial speed of 0 and acceleration of 6.12m/s^2.
For the green car:
With
and Xo = 200m
Since both positions will be the same:
Solving for t:
t1 = -5.8s and t1 =11.25s
Replacing t = 11.25 on either equation to find the displacement:

Answer:
I guess B
Explanation:
Because it stop by it self so that is digital
Answer is Option C
hope it helps you