Answer:
v =3.41 m/s
Explanation:
given,
mass of block 1 = 6 Kg
mass of another block 2 = 4 Kg
coefficient of friction = 0.3
Assuming 6 Kg block is attached to the spring of spring constant 350 N/m
and distance between the two block is equal to 0.5 m
using formula
U = 43.75 J
using conservation of energy
KE = U - f.d
where f is the frictional force acting
v =3.41 m/s
By definition, we have to:
Calcium Bromide is an inorganic salt formed by granular white crystals that responds to the formula CaBr2.
Calcium bromide has no odor, is colorless and has a bitter taste.
It is obtained by adding Hydrobromic Acid to Calcium Oxide, Calcium Carbonate or Calcium Hydroxide.
The substance that results is then subjected to a crystallization process, which involves evaporating the water.
From here, you get then:
CaBr2.
Answer:
CaBr2 = Calcium bromide.
Answer:
Se llama ángulo de incidencia -i- el formado por el rayo incidente y la normal. La normal es una recta imaginaria perpendicular a la superficie de separación de los dos medios en el punto de contacto del rayo. El ángulo de reflexión -r- es el formado por el rayo reflejado y la normal.
Answer:
calcium-47
Explanation:
Just did the test. Good Luck!
