Answer:
Depends on the person, if you are hooked to your phone which most people are these days, you might go a little crazy. But think cavemen or anybody long ago, they survived without electricity. People in Africa bathe in the lake or any water nearby, they also walk for miles just to get drinking water. So yes, if you really tried you could go without electricity for possibly your whole life. It sucks if you have homework though because you don't have Brainly :)
Explanation:
Answer:
500 THz .
Explanation:
Velocity of light in air = 3 x10⁸ m /s
wave length of light = 600 nm
= 600 x 10⁻⁹ m
= 6 x 10⁻⁷ m
frequency in air = velocity in air / wave length in air
= 3 x 10⁸ / 6 x 10⁻⁷
= .5 x 10¹⁵ Hz
= 5 x 10¹⁴Hz
= 500 x 10¹² Hz
= 500 THz
When light enters the medium of gem , its wavelength and velocity changes in such a way that its frequency remains constant. So in the medium of gem also its frequency remains 500 THz .
(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.
(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
<h3>
What is average velocity?</h3>
Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
average velocity = total distance / total time
v = (d)/(0.5d/v₁ + 0.5d/v₂)
where;
- v is the average velocity
- v₁ is the average velocity during the first half
- v₂ is the average velocity during the second half
90 km/h = (d) / (0.5d/48 + 0.5d/v₂)
90(0.5d/48 + 0.5d/v₂) = d
0.9375d + 0.5d/v₂ = d
d(0.9375 + 0.5/v₂) = d
0.9375 + 0.5/v₂ = 1
0.5/v₂ = 0.0625
v₂ = 0.5/0.0625
v₂ = 8 km/h
Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.
The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
Learn more about average velocity here: brainly.com/question/24739297
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Answer:
3.53 N/C
Explanation:
Electric field = F / q where F is the force in N and q is charge on the electron
F = mass of an electron × a ( acceleration in m/s)
using equation of motion to solve for the acceleration
s ( distance ) = ut + 0.5 at² since the electron is starting from rest then ut = 0
2s / t² = a
F = me × ( 2s / t²)
E electric field = me × ( 2s / t²) / q = me × 2s / ( t² × q)
me, mass of an electron = 9.11 × 10⁻³¹ kg
E = (9.11 × 10⁻³¹ kg × 2 × 0.038 m) / ( (3.5 × 10⁻⁷s)² × 1.6 × 10⁻¹⁹ C) = 0.0353 × 10² N/C = 3.53 N/C
Answer:
(a) 45 micro coulomb
(b) 6 micro Coulomb
Explanation:
C = 3 micro Farad = 3 x 10^-6 Farad
V = 15 V
(a) q = C x V
where, q be the charge.
q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb
(b)
V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad
q = C x V
where, q be the charge.
q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb
