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WITCHER [35]
3 years ago
13

Chemistry is the study of all of the following EXCEPT

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
4 0
B - projectile motion
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A student used 10 mL water instead of 30mL for the extraction of the NaCl from the mixture. How would this affect the calculated
Usimov [2.4K]
The amount of Nacl would be 3 times more
7 0
2 years ago
Plants such as _______________ provided much nitrogen to the soil.
Allushta [10]

Answer:

Abiotic

Explanation:

Its because it includes water, sunlight, tempature and soil

6 0
2 years ago
A student calculated that the amount of NaCl that should form in the lab (theoretical yield) is 2.50 grams. The actual amount fo
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0.92%. student calculated that the amount of NaCl that should form in the lab
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3 years ago
Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?
skad [1K]

<em>Answer:</em>

  • The option C is correct.
  • CH4N, 90g, C3H12N3.

<em>Explanation:</em>

                    <em>Option C:</em>

  • The molecular formula is C3H12N3.
  • If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N.
  • The molar mass of molecular formula = (12×3) + (1×12) +( 14×3) = 98 g

                <em>Option A :</em>

  • In option A , molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

              <em>Option B:</em>

  • In option B, molecular formual is not valid.
  • It should be as C6H16O2
4 0
3 years ago
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
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