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Anton [14]
2 years ago
13

What is the [H3O+] if the [OH-] is 1 x 10 -8?

Chemistry
1 answer:
Tanzania [10]2 years ago
5 0

From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M

<h3>What is concentration?</h3>

The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.

Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.

If that be the case, we are in order to write the expression;

[H3O+]  [OH-] = 1 * 10^-14

[H3O+] = 1 * 10^-14/ [OH-]

[H3O+] = 1 * 10^-14/ 1 x 10^ -8

[H3O+] = 1 * 10^-6 M

Learn more about concentration:brainly.com/question/10725862

#SPJ1

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The number of electrons in the outermost principal energy level of a chlorine atom is
Hitman42 [59]

Answer:

seven electrons

Explanation:

Chlorine is present in group seventeen of periodic table. It is halogen element. All halogens have seven electrons in outer most valance shell.

The require only one electron to gain the stable electronic configuration or to complete the octet.

Electronic configuration of chlorine:

Cl₁₇ = 1s² 2s² 2p⁶ 3s² 3p⁵

Abbreviated electronic configuration:

Cl₁₇ = [Ne] 3s² 3p⁵

Properties of chlorine:

1. it is greenish-yellow irritating gas.

2. its melting point is 172.2 K

3. its boiling point is 238.6 K

4. it is disinfectant and can kill the bacteria.

5. it is also used in manufacturing of paper, paints and textile industries.

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3 years ago
Who had the idea to study humans as groups rather than as individuals?
Vedmedyk [2.9K]
<span><span>V. C. Wynne-Edwards and Konrad Lorenz were the first authors to raise the concept of altruism</span><span>. This was later reiterated by  </span>David Sloan Wilson, E. O. Wilson and Elliott Sober<span> in 1994 whose works referred to social organisms such as ants</span></span>.




6 0
3 years ago
Read 2 more answers
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the
Fofino [41]

Answer:

(a) 102.6g/mol

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}

Solving for the molarity of base we've got:

M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L

Now, we can compute the moles of the base as:

n_{base}=0.425mol/L*0.1L=0.0425mol

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

\frac{4.36g}{0.0425mol} =102.6g/mol

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

102.6g/mol-16g/mol-1g/mol=85.6g/mol

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0
3 years ago
What is the definition of a common ion as it applies to Le Chatelier’s principle?
navik [9.2K]
The definition of a common ion as it applies to Le Chatelier's principle is an ion that is present in an equilibrium system and a compound added to the system. This is the case since in Le Chatelier's principle, it is based on an equilibrium system and where the reaction shifts to the left or to the right; towards the products or the reactants side.  
6 0
3 years ago
Read 2 more answers
Assuming tea leaves contain 5.0% caffeine by weight what is the maximum weight of caffeine you could isolate from 10.g of tea le
Fiesta28 [93]

Answer:

0.50 g Caffeine

Explanation:

Step 1: Given data

Concentration of caffeine by weight in tea leaves: 5.0%

Mass of tea leaves: 10. g

Step 2: Calculate the maximum weight of caffeine that can be isolated

The concentration of caffeine by weight in tea leaves is 5.0%, that is, there are 5.0 g of caffeine per 100 g of tea leaves. The maximum weight of caffeine in 10. g of tea leaves is:

10. g Tea leaves × 5.0 g Caffeine/100 g Tea leaves = 0.50 g Caffeine

7 0
3 years ago
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