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2 years ago

What is the [H3O+] if the [OH-] is 1 x 10 -8?

Chemistry

1 answer:

Tanzania [10]2 years ago

5 0

From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M

<h3>What is concentration?</h3>

The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.

Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.

If that be the case, we are in order to write the expression;

[H3O+] [OH-] = 1 * 10^-14

[H3O+] = 1 * 10^-14/ [OH-]

[H3O+] = 1 * 10^-14/ 1 x 10^ -8

[H3O+] = 1 * 10^-6 M

Learn more about concentration:brainly.com/question/10725862

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All of the following are true about the Earth’s inner core EXCEPT

Inessa05 [86]

that it is cooler than the lithosphere.

8 0

3 years ago

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

6 0

3 years ago

PLSSSSS HELPPPP......

rosijanka [135]

Answer: A

Explanation:
The buoyancy force only takes affect when an object is placed in water and floats. This occurs because the density of that object is less than the density of water.
Water is the main liquid used for measuring the density of an object.

Hope this helps! Please tell me if I am wrong :3

7 0

2 years ago

At 850 K, the equilibrium constant for the reaction

Sphinxa [80]

Answer:

Answers are in the explanation.

Explanation:

Given concentrations are:

SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M

SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M

And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M

In the reaction:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kc is defined as:

Kc = 15 = [SO₃]² / [O₂] [SO₂]²

Where concentrations of each species are equilbrium concentrations.

Also, you can define Q (Reaction quotient) as:

Q = [SO₃]² / [O₂] [SO₂]²

Where concentrations of each species are ACTUAL concentrations.

If Q > Kc, the reaction will shift to the left until Q = Kc;

If Q < Kc, the reaction will shift to the right until Q = Kc

If Q = Kc, there is no net reaction because reaction would be en equilibrium.

Replacing with given concentrations:

Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction

Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left

Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right

8 0

3 years ago

What conversion factor would you use to convert correctly from the mass of a given

statuscvo [17]

Answer: 1 mole of the substance is equal to its molar mass or vice versa.

Explanation: Example: 18 g H2O x 1 mole H2O / 18g H2O = 1 mole H2O

7 0

2 years ago