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Mamont248 [21]
3 years ago
10

you are attending a pumpkin chunkin event where they launch pumpkins by air cannon into a field. Calculate the acceleration of a

2kg pumpkin if launched by a force of 1930 N. Show your work and include units.
Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer:

The acceleration is 965 kg•ms^-2

Step-by-step explanation:

Mathematically;

Force = mass * acceleration

From the question;

Force = 1930 N (kg• ms^-2)

mass = 2kg

Acceleration = Force/mass = 1930/2 = 965 ms^-2

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\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3} is the maclaurin polynomial and estimate value of \sqrt{1.3} is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

<h3>Find the third order maclaurin polynomial:</h3>

Given the polynomial,

f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }

The formula to find the maclaurin polynomial,

f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}

Next we have to find f'(x), f''(x) and f'''(x),

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  • f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }
  • f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }

By putting x = 0 , we get,

  • f(0)=(1+3(0))^{\frac{1}{2} }=1
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  • f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}
  • f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}

Therefore the maclaurin polynomial by using the formula will be,

\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}

\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}

To find the value of \sqrt{1.3}  we can use the maclaurin polynomial,

\sqrt{1.3} is  \sqrt{1+3x} with x = 1/10,

\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}

\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14

Hence \sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3} is the maclaurin polynomial and estimate value of \sqrt{1.3} is 1.14.

Learn more about maclaurin polynomial here:

brainly.com/question/24188694

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Answer:

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A=6+3.5=9.5\ ft^2

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