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Brrunno [24]
3 years ago
6

What is the length of the x - component of the vector plotted below ?

Chemistry
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

3

Explanation:

You can make that into a triangle and find the hypotenuse by using the pythagorean theorem a^2 + b^2 = c^2

Your hypotenuse is your vector that you're looking for

Heres the work:

3^2 + 3^2= r^2

r=3

Please let me know if this helped, and rank it the brainliest if possible!

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ANSWER ASAP (20 POINTS)
SIZIF [17.4K]

Answer:

a chemical formula

Explanation:

5 0
3 years ago
You have a gas at a volume of 9.71 L at a pressure of 209 torr and at 10.1 °C. What
Usimov [2.4K]

Answer:

219.95 °C

Explanation:

Given data:

Volume of gas = 9.71 L

Initial pressure = 209 torr (209/760 = 0.275 atm)

Initial temperature = 10.1 °C (10.1 +273 = 283.1 K)

Final temperature = ?

Final pressure = 364 torr (364/760 =0.479 atm)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.275 atm / 283.1 K = 0.479 atm/T₂

T₂ = 0.479 atm × 283.1 K/ 0.275 atm

T₂ = 135.6 atm. K /0.275 atm

T₂ = 493.1 K

Kelvin to °C:

493.1 K - 273.15 = 219.95 °C

8 0
3 years ago
Which statement about protons is false?
Alekssandra [29.7K]

<u>Answer:</u> The correct answer is Option 4.

<u>Explanation:</u>

There are three sub-atomic particles present in an atom. They are: electrons, protons and neutrons.

Protons constitute in each and every atom.

The charge on proton is of equal magnitude as that of electron but having opposite sign. Proton carry a positive charge and electron carry a negative charge.

Protons and neutrons, both determine the mass of an atom.

Mass of 1 proton = 1.007276 u

Mass of 1 neutron = 1.008664 u

Mass of 1 electron = 0.00054858 u

Mass of proton is almost same as that of neutron but is more than the mass of electron.

Hence, the correct answer is Option 4.

6 0
3 years ago
The greater the resistance, the less current there is for a given voltage. True or False
mart [117]
True the answer is true
7 0
3 years ago
Read 2 more answers
At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
Alekssandra [29.7K]

Explanation:

Density =\frac{Mass}[Volume}

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball =V=560 cm^3=560 ml=0.560 L

D =\frac{0.12 g}{0.560 L}=0.214 g/L

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = d_1=1.830 g/L

Mass of the carbon dioxide gas :

1.830 g/L\times 0.560 L=1.0248 g

Total density of filled ball with carbon dioxide gas:

\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = d_2=0.0899 g/L

Mass of the hydrogen gas :

1.830 g/L\times 0.560 L=0.050344 g

Total density of filled ball with hydrogen gas:

\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = d_3=1.330 g/L

Mass of the oxygen gas :

1.330 g/L\times 0.560 L=1.7448 g

Total density of filled ball with oxygen gas:

\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165 g/L

Mass of the nitrogen gas :

1.165 g/L\times 0.560 L=0.6524 g

Total density of filled ball with nitrogen gas:

\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

\frac{0.12g +m}{0.560L}>1.189 g/L

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

5 0
3 years ago
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