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sergejj [24]
3 years ago
7

For the hexagonal close-packed crystal: (12 points) a. How many atoms are associated with the unit cell? b. What is the coordina

tion number? c. What is the atomic packing factor?
Chemistry
1 answer:
melomori [17]3 years ago
3 0

Answer :

(a) Total number of atoms in the cell = 6

(b) The coordination number of HCP is, 12

(c) The atomic packing factor is, 74.0 %

Explanation :

<u>Hexagonal close-packed structure (HCP) :</u>

Crystal structure : The manner in which the atoms or ions are spatially arranged.

(a) The HCP unit cell consist of three primitive unit cells in a hexagonal prism. That means, 3 atoms are in the middle layer and 12 atoms are at top and bottom layers and 2 face atoms.

So, the total number of atoms in the cell = 3 + (1/2)×2 + (1/6)×6 × 2 = 6

(b) Coordination number : It is defined as any constituent particle in a crystal is the number of its nearest neighbours.

The coordination number of HCP is, 12

(c) Packing fraction or factor : It is defined as the percentage of the total space filled by the particles.

\text{Packing factor}=\frac{n\times V_{atom}}{V_{cell}}\times 100

\text{Packing factor}=\frac{6\times (\frac{4}{3}\pi r^3)}{24\sqrt{2}r^3}\times 100

\text{Packing factor}=74.0\%

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What are atoms made of
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8 0
2 years ago
WILL MARK BRANILEST
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Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
3 years ago
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