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sergejj [24]
3 years ago
7

For the hexagonal close-packed crystal: (12 points) a. How many atoms are associated with the unit cell? b. What is the coordina

tion number? c. What is the atomic packing factor?
Chemistry
1 answer:
melomori [17]3 years ago
3 0

Answer :

(a) Total number of atoms in the cell = 6

(b) The coordination number of HCP is, 12

(c) The atomic packing factor is, 74.0 %

Explanation :

<u>Hexagonal close-packed structure (HCP) :</u>

Crystal structure : The manner in which the atoms or ions are spatially arranged.

(a) The HCP unit cell consist of three primitive unit cells in a hexagonal prism. That means, 3 atoms are in the middle layer and 12 atoms are at top and bottom layers and 2 face atoms.

So, the total number of atoms in the cell = 3 + (1/2)×2 + (1/6)×6 × 2 = 6

(b) Coordination number : It is defined as any constituent particle in a crystal is the number of its nearest neighbours.

The coordination number of HCP is, 12

(c) Packing fraction or factor : It is defined as the percentage of the total space filled by the particles.

\text{Packing factor}=\frac{n\times V_{atom}}{V_{cell}}\times 100

\text{Packing factor}=\frac{6\times (\frac{4}{3}\pi r^3)}{24\sqrt{2}r^3}\times 100

\text{Packing factor}=74.0\%

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Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:

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Li⁰(s) → Li⁺(aq) + e⁻   (2)

  • Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).  

We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.

In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

Learn more here:

  • brainly.com/question/10547418?referrer=searchResults
  • brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

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