Answer:
Explanation:
Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.
Mathematically, it can be represented as -
1 mol (Na) 
1 mol (Cl) 
g/mol
In 
gram of NaCl, there is one mole of Na or 
ions
In one gram of NaCl, there will be
sodium ions
In 
grams of NaCl, the number of sodium ions will be -
Explanation:
Atomic size is defined as the distance between the nucleus and valence shell of an atom. Valence shell is the outermost shell of an atom.
When we move across a period in a periodic table then there will occur a decrease in atomic size of the atoms. But when we move across a group in a periodic table then there will occur an increase in atomic size of the atom.
Hydrogen is a period 1 element, oxygen is a period 2 element, chlorine is a period 3 element and bromine is a period 4 element.
Therefore, given elements are arranged in order of increasing atomic size as follows.
H < O < Cl < Br
Answer: 0.217 mol
Explanation:
To find the amount of moles in a 10 g sample, we need the molar mass of ethanol.
Molar Mass: 46.07 g/mol
Now that we have the molar mass, we can find moles.
We know that there are 0.217 mol in a 10.0 gram sample.
<em> $ 434.40</em>
<em>41 miles ............ 1 gallon</em>
<em>4700 miles .......x gallon</em>
<em>x = 4700×1/41 = 114.63 gallons</em>
<em />
<em>114.63 gallons×$3.79 ≈ $ 434.40</em>
Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
