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zloy xaker [14]
3 years ago
15

Solve the following system of equations using substitution. What is the value of y?

Mathematics
1 answer:
erastova [34]3 years ago
3 0
I have no idea how did you get this result but I can show you the method of elimination. I think that it is the easiest way to solve the system of equations.
2 x + 3 y =105
x + 2 y = 6  /*(-2)      // We will multiply 2nd equation by -2. That is because                                         we want to cancel out the x`s//
2 x + 3 y = 105
-2 x - 4 y = -12        // Then we will add down these equations/ and x`s will                                          cancel out//
3 y - 4 y = 105 - 12
- y = 93
y = -93
We can also solve x:
x + 2 * (-93)=6
x - 186 = 6
x = 6 + 186
x = 192 
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FREE BRAINLIEST. PLEASE ANSWER STEPBY STEP 1. 2. 3.
Flura [38]

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8

Step-by-step explanation:

First do whats in the parenthesis:

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3 0
3 years ago
If MN=NQ and MQ=QR=RP, calculate for x​
Akimi4 [234]

Answer:

  • C. 18°

Step-by-step explanation:

  • <em>Refer to attached diagram</em>
<h3>Given </h3>
  • MN = NQ
  • MQ = QR = RP
  • NMR = 3x
  • QMR = x
<h3>To find</h3>
  • Value of x
<h3>Solution</h3>
  • MN = NQ  ⇒ ∠MRN = ∠QMN = 3x+x = 4x
  • MQ = QR ⇒ ∠MRQ = ∠QMR = x

<u>RQP is exterior angle of ΔMQR ⇒ </u>

  • ∠RQP = x + x = 2x

<u>QR = RP ⇒ </u>

  • ∠RPQ = ∠RQP = 2x

<u>∠QRN is exterior angle of ΔQRP ⇒ </u>

  • ∠QRN = 2x + 2x = 4x
  • ∠MRN = ∠QRN - ∠QRM = 4x - x = 3x

<u>∠MRN = ∠NMR = 3x ⇒ </u>

  • NR = MQ

<u>NR = MQ ⇒ </u>

  • ∠NQR = ∠QRN = 4x

<u>We now have a straight angle MQP:</u>

  • ∠MQP = ∠MQN + ∠RQN + ∠RQP
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  • 10x = 180°
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Correct choice is C

7 0
3 years ago
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nikitadnepr [17]
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A. 3 + x = 8
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Subtract 3 4/5 from 13 4/5 to find the weight of w
w = 10

Let me know if you have questions about this.
7 0
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