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son4ous [18]
3 years ago
9

Un cuerpo recibe una fuerza de 100N y produce una aceleracion de 2 m/s² determine la masa del cuerpo

Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

The mass of the body is 50 kg.

Explanation:

We have,

Force acting on a body is 100 N

Acceleration of the body is 2 m/s²

It is required to find the mass of the body. The force acting on a body is given by :

F = ma

m=\dfrac{F}{a}\\\\m=\dfrac{100}{2}\\\\m=50\ kg

So, the mass of the body is 50 kg.

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Why is knowing the direction of the force important?
vodomira [7]
Knowing the direction of a force is important because it helps someone know the motion of the object. if you use a free body diagram, then it becomes easy to see all the forces being applied to an object. if there is more force going one way, the object is accelerating in that direction. if all the forces cancel each other out, then the object is at a constant speed or is at rest.
4 0
3 years ago
Insurance can help you
RUDIKE [14]
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7 0
3 years ago
A 88.6-kg wrecking ball hangs from a uniform heavy-duty chain having a mass of 26.9kg . (Use 9.80m/s2 for the gravitational acce
Dafna11 [192]

Answer:

Tension maximum =1131.9 N

Tension minimum =868.28 N

Tension at 3/4= 1065.995 N

Explanation:

a)

Given Mass of wrecking ball M1=88.6 Kg

Mass of the chain M2=26.9 Kg

Maximum Tension Tension max=(M1+M2) × (9.8 m/s²)

=(88.6+26.9) × (9.8 m/s²)

=115.5 × 9.8 m/s²

Tension maximum =1131.9 N

b)

Minimum Tension Tension minimum=Mass of the wrecking ball only × 9.8 m/s²

=88.6 × 9.8 m/s²

Tension minimum =868.28 N

c)

Tension at 3/4 from the bottom of the chain =In this part you have to use 75% of the chain so you have to take 3/4 of 26.9

= (3/4 × 26.9)+88.9) × 9.8 m/s²

= (20.175+88.6) × 9.8 m/s²

=(108.775) × 9.8 m/s²

=1065.995 N

6 0
4 years ago
Electrons with energy of 25 eV have a wavelength of ~0.25 nm. If we send these electrons through the same two slits (d = 0.16 mm
kupik [55]

Answer:

The spacing is 5.15 μm.

Explanation:

Given that,

Electron with energy = 25 eV

Wave length = 0.25 nm

Separation d= 0.16 mm

Distance D=3.3 m

We need to calculate the spacing

Using formula of width

\beta=\dfrac{\lambda D}{d}

Put the value into the formula

\beta=\dfrac{0.25\times10^{-9}\times3.3}{0.16\times10^{-3}}

\beta=5.15\times10^{-6}\ m

\beta=5.15\ \mu m

Hence, The spacing is 5.15 μm.

7 0
3 years ago
A generator has a 100-turn coil that rotates in a 0.30-T magnitude B-field at a frequency of 80 Hz. The area of each loop is 0.0
loris [4]

Answer:

Explanation:

Flux Φ = nBA sinωt

t = 0 , flux = 0

dΦ / dt = nωBA Cosωt

e = nωBA Cosωt

= 100 x 2πx80 x.3 x .003 cos 2πx80 x .014

= 45.21 cos 7.0336

= 33.0668 v

= 33.1 V

4 0
3 years ago
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