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AlladinOne [14]
3 years ago
11

What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.4 T?

Physics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

The acceleration of the proton is 8.714 x 10⁸ m/s².

Explanation:

Given;

speed of the proton, v = 6.5 m/s

magnetic field strength, B = 1.4 T

The magnetic force on the proton is given as;

F = qvB

The force of the moving proton is given as;

F = ma

Thus, ma = qvB

where;

m is mass of proton = 1.673 x 10⁻²⁷ kg

q is charge of proton = 1.602 x 10⁻¹⁹ J

a is the acceleration of the proton

a = \frac{qvB}{m} \\\\a = \frac{1.602 \times 10^{-19} \times6.5 \times 1.4}{1.673\times10^{-27}}\\\\a = 8.714 \times 10^8 \ m/s ^2

Therefore, the acceleration of the proton is 8.714 x 10⁸ m/s².

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The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

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v = u + at

0 = 9.5 + a (2)

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brainly.com/question/27126557

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