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AlladinOne [14]
2 years ago
11

What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.4 T?

Physics
1 answer:
Vanyuwa [196]2 years ago
4 0

Answer:

The acceleration of the proton is 8.714 x 10⁸ m/s².

Explanation:

Given;

speed of the proton, v = 6.5 m/s

magnetic field strength, B = 1.4 T

The magnetic force on the proton is given as;

F = qvB

The force of the moving proton is given as;

F = ma

Thus, ma = qvB

where;

m is mass of proton = 1.673 x 10⁻²⁷ kg

q is charge of proton = 1.602 x 10⁻¹⁹ J

a is the acceleration of the proton

a = \frac{qvB}{m} \\\\a = \frac{1.602 \times 10^{-19} \times6.5 \times 1.4}{1.673\times10^{-27}}\\\\a = 8.714 \times 10^8 \ m/s ^2

Therefore, the acceleration of the proton is 8.714 x 10⁸ m/s².

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A 32.5 g cube of aluminum initially at 45.8 °C is submerged into 105.3 g of water at 15.4 °C. What is the final temperature of b
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Answer:

T = 17.26 ^oC

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On Earth, 1 kg = 9.8 N = 2.2 lbs. On the Moon, 1 kg = 1.6 N = 0.37 lbs. Use these relationships to answer the following question
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(b) 80 N on earth

(c) 45.4545 kg on earth

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Explanation:

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And 1 kg = 1.6 N = 0.37 lbs on moon

(a) We have given mass of the person m = 50 kg

As it is given that 1 kg = 9.8 N

So 50 kg = 50×9.8 =490 N

(b) Mass of the person on moon = 50 kg

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3 years ago
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