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3 years ago

How much work is done if I use 5N of force to move an object 2 meters

Physics

2 answers:

alina1380 [7]3 years ago

6 0

W=Fd. W=5•2=10. It’d be 10 joules.

frez [133]3 years ago

5 0

Answer:

Explanation:the forumla fr work is force times distance so 10 hope this helps god bless

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The uncertainty in the position of an electron along an x axis is given as 68 pm. What is the least uncertainty in any simultane

umka21 [38]

Answer:

$\Delta p_x=7.75\times 10^{-25}\ kg-m/s$

Explanation:

Given that,

The uncertainty in the position of an electron along the x-axis is, $\Delta x=68\ pm=68\times 10^{-12}\ m$

We need to find the east uncertainty in any simultaneous measurement of the momentum component of this electron.

We know that the Heisenberg's uncertainty principle gives the relation between the uncertainty in position and the momentum of electron as :

$\Delta p_x{\cdot}\Delta x\ge \dfrac{h}{4\pi }$

Putting all the values, we get :

$\Delta p_x{\cdot}\ge \dfrac{h}{4\pi \Delta x}\\\\\Delta p_x \ge \dfrac{6.63\times 10^{-34}}{4\pi \times 68\times 10^{-12}}\\\\\Delta p_x\ge 7.75\times 10^{-25}\ kg-m/s$

So, the momentum component of this electrons is greater than $7.75\times 10^{-25}\ kg-m/s$ .

6 0

3 years ago

Two skaters, one with mass 52.5 kg and the other with mass 26.3 kg, stand on an ice rink holding a pole with a length of 5.00 m

Marizza181 [45]

Answer: 10.02m

Explanation: Given

M1 = 26.3kg

M2 = 52.5kg

d = 5m

If the systems centre of mass does not change, the two skaters will definitely meet at the centre of mass.

If the 26.3kg skater is a m away from the centre of the mass, then the 52.5kg skater is (5-a) m away from the centre of the mass. Thus,

M1a + M2(5-a) = 0

26.3a + 52.5(5-a) = 0

26.3 a + 262.5 - 52.5a = 0

-26.2a + 262.5 = 0

26.2a = 262.5

a = 262.5/26.2

a = 10.02m

5 0

3 years ago

A heavy object falls with the acceleration as a light object during free fall. why?

alexgriva [62]

<u>A heavy object falls with the acceleration as a light object during free fall because:</u>

Heavy things have a large gravitational force and also have less acceleration. So both the effects exactly cancel and make the falling objects to have the same acceleration irrespective of mass.

Free fall is a unique motion which has only gravitational force that acts on an object. Objects that undergo free fall experience only have the influence of gravity and not any other force.

So when we apply newton's second law of gravity which is:

$\text {acceleration}=\frac{\text {Force}}{\text {mass}}$

where,

F is the force

m is the mass

a is the acceleration

For example: When a 1000 kg elephant and a 1 kg rat fall from the same height,

The acceleration can be calculated as follows:

For elephant: F = 10000 N and m = 1000 kg. So,

$\text {acceleration}=\frac{10000}{1000}=10\ \mathrm{m} / \mathrm{s}^{2}$

For rat : F = 10 N and m = 1 kg

Thus, $\text {acceleration}=\frac{10}{1}=1\ \mathrm{m} / \mathrm{s}^{2}$

Hence, it shows that both the animals have the same acceleration irrespective of their mass.

6 0

3 years ago

Ne4ueva [31]

Answer:

d solid

Explanation: brainlist plz

solids have a definite shape and volume

8 0

3 years ago

In tests on earth a lunar surface exploration vehicle (mass = 5.57 × 103 kg) achieves a forward acceleration of 0.207 m/s2. to a

spayn [35]

The answer is 9000 or b

5 0

3 years ago