Radius into radius .You should know half of diameter is radius.
Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
<u>e</u>
Step-by-step explanation:
According to Angle Sum Property :
<u>∠A + ∠B + ∠C = 180°</u>
<u />
============================================================
Given :
⇒ ∠A = 50°
⇒ ∠B = 32°
===========================================================
Solving :
⇒ 50° + 32° + ∠C = 180°
⇒ ∠C + 82° = 180°
⇒ ∠C = <u>98°</u>
Answer: the first one is the answer I think
Step-by-step explanation:
The answer would be C.
Sin2 cot2=sin2*cos2/sin2=cos2
Which is not equal to the others.
Hope this helps:)
