Answer:
A)0.00966 N/C
B) counterclockwise direction
Explanation:
We are given;
Diameter of the metal ring; d = 4.3 cm
Radius;r = 2.15 cm = 0.021- m
Initial magnetic field, B = 1.12 T
Rate of decrease of the magnetic field;dB/dt = 0.23 T/s
Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :
∫E•dr = d/dt∫B.A •dA
This gives;
E(2πr) = dB/dt(πr²)
Gives;. 2E = dB/dt(r)
E = dB/dt × 2r
We are given;
E = 0.23 × 2(0.021)
E = 0.00966 N/C
The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C
B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet
Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Answer: A. They will be repelled because they are in each other's magnetic
field.
Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.
At the highest point: kinetic energy is 0 due to the speed is 0
So the total mechanical energy is 20
Assume no frictions present, then the mechanical energy is conserved
So at the lowest point, kinetic energy = mechanical energy - potential energy
Answer will be 20 - 0.5 = 19.5 J
