To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
I do belive that it is 10 because whole numbers arnt irrational numbers
Answer: 33.33%
Step-by-step explanation:
Answer:
- m=y2-y1 / x2-x1
- m= 5-2 / 9-0
- 3/9 =1/3
- y=mx+b
- 2=1/3(0)+b
- 2=b
- slope is 1/3
- y-intr is 2
Step-by-step explanation:
Answer: 3/7 sorry if wrong
Step-by-step explanation: