Answer:
![[HCl]_{eq}=0.05M](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3D0.05M)
Explanation:
Hello,
In this case, for the given chemical reaction, the law of mass action at equilibrium results:
![Kc=\frac{[H_2]_{eq}[Cl_2]_{eq}}{[HCl]^2_{eq}}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D_%7Beq%7D%5BCl_2%5D_%7Beq%7D%7D%7B%5BHCl%5D%5E2_%7Beq%7D%7D)
Next, in terms of the change 
due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:
Thus, solving for via quadratic equation or solver, the following results are obtained:
Clearly, the solution is 
as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:
![[HCl]_{eq}=0.25M-2*0.1M](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3D0.25M-2%2A0.1M)
Best regards.
The answer is Water and carbon dioxide
there are seven valence electrons<span> available of bonding in bromine(Br)</span>
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