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Zigmanuir [339]
2 years ago
15

1.

Chemistry
1 answer:
Mama L [17]2 years ago
6 0

The question is incorrect, the correct question is;

Which of the following ground-state electron configurations represents the atom that has the

lowest first-ionization energy?

a) 1s2

b) 1s22s2

c) 1s22s22p6

d) 1s22s22p63s23p1

e) 1s22s22p63s23p3

The correct ground state configuration that represents the atom that has the lowest first ionization energy is 1s² 2s² 2p⁶ 3s² 3p¹.

The first ionization energy is the energy required to remove an electron from the outermost shell of an atom.

Ionization energy decreases down the group as number of shells increases but increases across the period as nuclear charge increase.

As the number of shells increases, the degree of shielding or screening decreases it easier to remove the outermost electron.

The elements whose ground state electronic configurations were shown are;

Helium - 1s²  

Beryllium - 1s² 2s²  

Neon - 1s² 2s² sp⁶  

Aluminum - 1s² 2s² 2p⁶ 3s² 3p¹    

Phosphorus - 1s² 2s² 2p⁶ 3s² 3p³

Aluminium (1s² 2s² 2p⁶ 3s² 3p¹) is a metal so it has the lowest first ionization energy since metals are highly electropositive.

Learn more: brainly.com/question/17783060

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Which accurately completes the statement? Conduction involves the transfer of ___________ due to the movement of particles. Grou
Jlenok [28]

Explanation:

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5 0
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All of the above would be the answer


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8 0
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In methane combustion, the following reaction pair is important: At 1500 K, the equilibrium constant Kp has a value of 0.003691
andre [41]

Explanation:

Let us assume that the value of K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s

Also at 1500 K, K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s

                     K_{r} = 400.613 m^{6}/mol^{2}s

Relation between K_{p} and K_{c} is as follows.

                  K_{p} = K_{c}RT

Putting the given values into the above formula as follows.

                  K_{p} = K_{c}RT

         0.003691 = K_{c} \times 8.314 \times 1500

                K_{c} = 2.9 \times 10^{-7}

Also,     K_{c} = \frac{K_{f}}{K_{r}}

or,                K_{f} = K_{c} \times K_{r}

                               = 2.9 \times 10^{-7} \times 400.613

                               = 1.1617 \times 10^{-4} m^{6}/mol^{2}s

Thus, we can conclude that the value of K_{f} is 1.1617 \times 10^{-4} m^{6}/mol^{2}s.

6 0
3 years ago
The highly reactive elements in group 7a are known for forming salts.what are they called
yaroslaw [1]
Group 7A are halogens 

If you look at a periodic table, these elements include F, Cl, Br, I, and At. Some well known salts are KCl and NaCl (better known as table salt!)
7 0
3 years ago
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