Answer:
The molality of solution=12.605 m
Explanation:
We are given that
Molar mass of Hydrogen peroxide, M=34 g/mol
Density of solution,
30% Means mass of solute (Hydrogen peroxide)=30 g
Mass of solvent =100-30=70 g
Total mass of solution, m=100 g
Number of moles of solute=
Using the formula
Number of moles of hydrogen peroxide=
Now, molality of solution
Hence, the molality of solution=12.605 m
Answer:
I thinks it's c
Explanation:
cold air is denser than hot air so it sinks.
Answer:
1. 0.74mol
2. 0.42mol
3. 2.125mol
4. 0.301mol
5. 4.52 × 10^23 particles
Explanation:
Number of moles (n) in a substance can be found using the formula:
mole (n) = mass/molar mass
Using this formula, the following moles are calculated:
1. Molar of Na = 23g/mol
mole = 17/23
mole = 0.74mol
2. Molar mass of Na2SO4 = 23(2) + 32 + 16(4)
= 46 + 32 + 64
= 142g/mol
Mole = 60/142
mole = 0.42mol
3. Molar mass of CO2 = 12 + 16(2)
= 12 + 32
= 44g/mol
mole = 93.5/44
mole = 2.125mol
4. Molar mass of sodium nitrate (NaNO3) = 23 + 14 + 16(3)
= 23 + 14 + 48
= 85g/mol
mole = 25.6/85
mole = 0.301mol
5. Number of particles in one mole of a substance is 6.022 × 10^23 particles. Hence, in 0.75mol of calcium hydroxide (Ca(OH)2, there will be;
0.75mol × 6.02 × 10^23
= 4.515 × 10^23
= 4.52 × 10^23 particles
Answer: When light passes through water, when its sunny, but most likely after a thunderstorm
Explanation:
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