Given two points (x₁,y₁) and (x₂,y₂) the slope of the line that passes through theses points will be:m=(y₂-y₁)/(x₂-x₁)
We have two points A(-2,-2) and B(2,-2); therefore the slope will be:m=(-2+2)/(2+2)=0/4=0
slope-intercept form:y=mx +bm=slopeb=y-intercept =-2
y=0x-2y=-2
Answer: The slope of diagonal AB is 0 and its equation is y=-2
Answer:
-58
Step-by-step explanation:
8*3*-2=-48
-48-2*5=-58
Answer:
If you choose any value for k other than 6, that will be give you the one solution.
If k=6, you have no solutions because the lines will be parallel.
Step-by-step explanation:
We are going to put each of this in y=mx+b where m is the slope and b is the y-intercept.
kx+2y=5
Subtract kx on both sides:
2y=-kx+5
Divide both sides by 2:
y=(-k/2)x+(5/2)
The slope is -k/2 and the y-intercept is 5/2
3x+y=1
Subtract 3x on both sides:
y=-3x+1
The slope is -3 and the y-intercept is 1.
We want the system to have one solution so we want the slopes to be difference.
So we don't want (-k/2)=(-3).
Multiply both sides by -2: k=6.
We won't want k to be 6.
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