Answer:
The speed of the 11.5kg block after the collision is V≅4.1 m/s
Explanation:
ma= 4.8 kg
va1= 7.3 m/s
va2= - 2.5 m/s
mb= 11.5 kg
vb1= 0 m/s
vb2= ?
vb2= ( ma*va1 - ma*va2) / mb
vb2= 4.09 m/s ≅ 4.1 m/s
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<span>The equation to be used here would be:
v = u - gt
where u is the initial speed, g is the acceleration due to gravity and t is the time it takes
a)
u = 28 m/s, g = 9.8 m/s^2, t = 2s
v = 28 m/s - 9.8 m/s^2 * 2s = 8.4 m/s
after 2 s the lava bomb is still travelling upwards
b)
u = 28 m/s
g = 9.8 m/s^2 t = 3s
v = 28 m/s - 9.8 m/s^2 * 3s = -1.4 m/s after 3s the lave bomb is travelling downwards</span>
