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IRINA_888 [86]
2 years ago
11

Two positive charges, 91 = 5 x 10-'[C] and q2 =1 x 10-9 [C], are

Physics
1 answer:
denis23 [38]2 years ago
4 0

Answer:

wareffctgggyyggghhhh

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Caso #1 Leo Messi está jugando la final de la Champion league 2019-2020 y va a cobrar un tiro libre importante, necesita aplicar
kramer

Answer:

Tiene que patear el balón cerca del nivel del suelo para conseguir el gol.

Explicación:

Leo Messi necesita patear el balón no en el aire, en el nivel del suelo para poder meter el gol para el equipo. Delante del fútbol hay muchos jugadores del equipo contrario dispuestos a detener el tiro libre de Leo Messi. Cuando Leo Messi patea el balón en el aire, los jugadores también saltan en el aire para detener el tiro libre que atraviesa la cabeza y para conseguir el gol Leo Messi tiene que evitar patear el balón en el aire y patear el balón cerca del nivel del suelo. que puede atravesar a los jugadores oponentes cuando lo saltan para detener el balón a través de sus cabezas para que el balón pase por debajo de sus pies y llegue a la portería.

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3 years ago
What is the difference between work done by the gravitational force on descending and ascending objects?
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Why is it more helpful to know a tornadoes velocity rather than its speed
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3 years ago
Read 2 more answers
A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a
stira [4]

Answer:

Explanation:

Given

acceleration is given by

a=-g-c_Dv^2

where \ddot{y}=a

\dot{y}=v

Also acceleration is given by

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ds=\frac{v}{a}dv

\int ds=\int \frac{v}{-g-0.001v^2}dv

\Rightarrow Let -g-0.001v^2=t

-0.001\times 2vdv=dt

vdv=-\frac{dt}{0.002}

at\ v_0=50\ m/s,\ t=-g-0.001(50)^2

t=-g-2.5

at v=0,\ t=-g

\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}

\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}

s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}

s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})

s=113.608\ m

when air drag is neglected maximum height reached is

h=\frac{v_0^2}{2g}

h=\frac{50^2}{2\times 9.8}

h=127.55\ m

3 0
3 years ago
The magnitude of a force is:
lys-0071 [83]

Answer:

c

Explanation:

force is how hard it is pulled or pushed

3 0
3 years ago
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