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IRINA_888 [86]
2 years ago
11

Two positive charges, 91 = 5 x 10-'[C] and q2 =1 x 10-9 [C], are

Physics
1 answer:
denis23 [38]2 years ago
4 0

Answer:

wareffctgggyyggghhhh

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What can cause a production possibilities curve to move to the right?
Bas_tet [7]

Answer:

Option D

a new invention lowers the cost of production

Explanation:

When there is a new invention lowers the cost of production, the production is likely to increase since the time allocated is as previous. Therefore, the curve moves to the right, to indicate a positive direction

5 0
3 years ago
Power is the rate at which...........is done or the rate at which........... is converted from one form to another .
34kurt

Answer:

the answer is c I thought

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2 years ago
What would make oppositely charged objects attract each other more?
Lady_Fox [76]

Answer:

A. increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object

Explanation:

4 0
3 years ago
Read 2 more answers
4. Which of the following would NOT be a major process in the formation of sedimentary
sladkih [1.3K]

Answer:

b. melting

Explanation:

it is made of sediments and that is not necessary

5 0
2 years ago
The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
3 years ago
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