1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex_Xolod [135]
3 years ago
11

An object is 39 cm away from a concave mirrors surface along the principles axis. If the mirrors focal length is 9.50 cm, how fa

r away is the corresponding image?
Physics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

12.6 cm

Explanation:

We can use the mirror equation to find the distance of the image from the mirror:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where here we have

f = 9.50 cm is the focal length

p = 39 cm is the distance of the object from the mirror

Solving the equation for q, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{9.50 cm}-\frac{1}{39 cm}=0.080 cm^{-1}\\q = \frac{1}{0.080 cm}=12.6 cm

You might be interested in
You walked a line 100 meters north, then 100 meters west, then 100 meters south. Which is true?
dangina [55]

Answer:

distance is 300 m and displacement is 100 m

Explanation:

7 0
3 years ago
A vertical spring with a spring constant of 2.00 N/m has a 0.30-kg mass attached to it, and the mass moves in a medium with a da
Ugo [173]

Answer:

17 seconds

Explanation:

Given that:

The mass attached to the spring (m) = 0.30 kg

The spring constant (k) =  2.00 N/m

The damping constant (b) = 0.025 kg/s

The initial distance x_o = 5.0 cm

The initial final amplitude A_f = 2.5 cm and not 2.5 m, please note the mistake, if it is 2.5 m, our time taken will be -93.7 sec, and we do not want a negative time value.

To start with the angular frequency damping using the formula:

\omega_{\gamma}= \dfrac{b}{2m}

\omega_{\gamma}= \dfrac{0.025 \ kg/s}{2(0.3 \ kg)}

\omega_{\gamma}=4.167 \times 10^{-2} \ s^{-1}

In the absence of damping, the angular frequency is:

\omega_o = \sqrt{\dfrac{k}{m}}

\omega_o = \sqrt{\dfrac{2 \ N/m}{0.3 kg}} \\\\\omega_o = 2.581 \ s^{-1}

The initial amplitude oscillation can be computed by using the formula:

A_i = e^{-\omega_{\gamma}t} x_o \sqrt{\dfrac{\omega_o^2}{\omega_o^2-\omega_f^2}}

A_i = e^{-\omega_{\gamma}0} (5.0 \ cm) \sqrt{\dfrac{2.581^2}{2.581^2-(4.167*10^{-2})^2}}

A_i = 5.0006 \ cm \\ \\  A_i = 5.001 \ cm

The final amplitude, as well as the initial amplitude, can be illustrated by using the relation:

A_f = e^{-\omega_{\gamma}t}A_i\\ \\ e^{-\omega_{\gamma}t} = \dfrac{2. 5 \  cm}{5.001 cm}\\ \\  = 0.4999\\ \\ \implies   -\omega_{\gamma}t_f = \mathsf{In (0.4999)} \\ \\  t_f = \dfrac{\mathsf{-In (0.4999)}}{4.167*10^{-2} \ s^{-1}} \\ \\

t_f = 16.64 \ sec \\ \\  \mathbf{t_f \simeq  17 sec}

5 0
3 years ago
When water is boiled at a pressure of 2.00 atm, the heat of vaporization is 2.20×106J/kg2.20×10
Grace [21]

Answer:

Explanation:

a ) When 1 kg water is boiled at constant pressure of 1  atm , its volume increases by following volume

(.824 - .001 )m³

.823 m³

work done by steam  = increase in volume x pressure

.823 x 10⁵ J

Heat added

=  latent heat of vaporization x mass

= 2260000 J x 1

= 22.6 x 10⁵ J

Increase in internal energy of gas

= heat added - work done by gas

= (22.6 - .823) x 10⁵ J

= 21.777 x 10⁵ J .

5 0
3 years ago
Sound wave is an example of ……………………………………. wave.
katrin [286]

Answer:

4

Explanation:

longitudinal

have a beautiful day ahead

6 0
2 years ago
Need answer fast plz
vazorg [7]

Answer:

a = 1.20m\s^{2}

Explanation:

225 x 9.8

= 441N

-

710 - 441

= 269N

-

\frac{269}{225} = 1.19

a = 1.20

8 0
3 years ago
Other questions:
  • Can someone please help me with photography questions​
    13·1 answer
  • ANSWER QUICKLY!!!!!
    7·2 answers
  • A person lying on an air mattress in the ocean rises and falls through one complete cycle every 3.00 seconds. The crests of the
    12·1 answer
  • Intr- un vas de forma cubica cu latura de 0, 4m se afla un volume de 2 l de apa
    13·2 answers
  • What is the difference between mass and weight?
    10·2 answers
  • In a four stroke engine, the piston compresses the gas mixture during the ______ stroke.
    11·1 answer
  • An object in the shape of a thin ring has radius a and mass M. A uniform sphere with mass m and radius R is placed with its cent
    6·1 answer
  • You are standing 5 m from a loud machine. You move 10 m from the machine to help reduce the intensity of the sound. Calculate th
    15·1 answer
  • Can someone please help me!!!!!​
    15·1 answer
  • 1. A car has a mass of 400 kg and is driving down a hill at 2 m/s/s. What is the force of the car?​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!