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4 years ago

What existed during the mesozoic era

1 answer:

3 0

Mezoic era began 252m years ago and ended 6.6m years ago.
It was a time of geological and biological transition. During this era the continents began to drift to their present configuration.
3 of the largest mass extinction occurred at this era. One which include the dinosaurs.
I hope this helped. :)

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At higher temperatures, air can hold __vapor as compared to air at lower?

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Answer:

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the density of ethanol is 0.789g/ml at 20°c. find the mass of a sample of ethanol that has a volume of 150.0 ml at this temperat

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3 years ago

In 1953, who devopled the model that is shown below

PilotLPTM [1.2K]

What model? can you screenshot it or send a link?

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According to the phase diagram for water, how is the state of water determined?

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3 years ago

Read 2 more answers

Given that a sample of air is made up of nitrogen, oxygen, and argon in the mole fraction 0.78 N2, 0.21 O2, and 0.010 Ar, what i

Artist 52 [7]

Answer:

1.293 kg/m³

Explanation:

Density: this can be defined as the ratio of the mass of a body and its volume.

The S.I unit of density is kg/m³

D = m/v............................ Equation 1

D = density of air, m = mass of air, v = volume of air.

<em>Note: Since the air is made up of nitrogen, oxygen and argon. the mass and volume of air will be the sum of the mass and sum of the volume of nitrogen, oxygen, and argon respectively.</em>

(i) Mass of one mole of N₂ = 28 g

Therefore, mass of 0.78 mole of N₂ = 28×0.78 = 21.84 g.

(ii) Mass of one mole of O₂ = 32 g

Therefore, mass of 0.21 mole of O₂ = 32×0.21 = 6.72 g

(iii) Mass of one mole of Ar = 40 g

Therefore mass of 0.01 mole of Ar = 0.01×40 = 0.4 g

m = 21.84 + 6.72 + 0.4 = 28.96 g

Also Note: One mole of every gas at standard temperature and pressure = 22.4 dm³

Therefore,

(i) volume of 0.78 mole of N₂ = 22.4×0.78 = 17.47 dm³

(ii) volume of 0.21 mole of O₂ = 0.21×22.4 = 4.704 dm³

(iii) volume of 0.01 mole of Ar = 0.01×22.4 = 0.224 dm³

Therefore,

v = 17.47+4.704+0.224

v = 22.398 dm³

Substituting the value of v and m into equation 1

D = 28.96/22.398

D = 1.293 g/dm³

D = 1.293 kg/m³

5 0

4 years ago

Read 2 more answers