Explanation:
Given parameters:
Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole
Unknown:
Mass of the sulfur trioxide = ?
Solution:
To solve for the mass of the sample of sulfur trioxide:
- Find the molar mass of the compound i.e SO₃
atomic mass of S = 32g
O = 16g
molar mass = 32 + 3(16) = 80g/mol
mass of SO₃ = number of moles x molar mass
mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg
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mole calculation brainly.com/question/13064292
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Rows are periods, columns are groups
Their identified by the number of protons they have in the nucleus which = their electrons.
The enthalpy of this reaction is -296. 8 kJ/mol.
The equation of the reaction is;
S(s) + O2(g) -----> SO2(g)
Recall that the enthalpy of the reaction can be obtained from the formula;
ΔHrxn = ΔHf(products) - ΔHf(reactants)
We know that;
ΔHf S(s) = 0 KJ/mol
ΔHf O2(g) = 0 KJ/mol
ΔHf SO2(g) = -296. 8 kJ/mol
Hence;
ΔHrxn = -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]
ΔHrxn = -296. 8 kJ/mol
Learn more: brainly.com/question/13164491
