Can't say i can answer this. :/
Answer:
Cr 6+ & SO4 2-
Explanation:
Sulfate is a polyatomic ion that has a charge of 2-. There are three of them in the chemical formula so it equates to a 6- total charge. Thus, chromium must have a 6+ charge to give the compound a neutral charge.
The equilibrium constant "k" is used to determine the concentration of every product in a reversible reaction until equilibrium is reached. At equilibrium, the value of k is equal to 1.
When the value of k is less than 1, this means that the concentration of the reactants is more than the concentration of the products. To reach equilibrium again, the reaction will shift to the left forming more products to compensate for the concentration.
Based on this, there are only two choices which are:
<span>The concentration of one or more of the products is small.
</span><span>The reaction will not proceed very far to the right.
The other two are incorrect as:
The concentration of the reactants is more and not less
The reaction will generally form more products than reactants.</span>
Molarity of Ag+ is less than the molar solubility thus ppt will not occur.
Balanced reaction-:
<h3>2AgNO3(aq)+K2CrO4(aq)→Ag2CrO4(s)+2KNO3(aq)</h3>
Moles of AgNO3=mass(g)molar mass (g/mol) =2.7×10−5g / 169.86 gmol
=1.589⋅10^−7 mol
Molarity of Ag+=moles of solute(L)=1.589⋅10−7 mol0.015 L=1.059⋅10−5M
Ksp of Ag2CrO4
=[Ag+]2[CrO42−]
1.2⋅10−12=[2s]2[s]
4s3=1.2⋅10−12
s=6.69⋅10−5 M
Molarity of Ag+ is less than the molar solubility thus ppt will not occur.
<h3>What is the molarity calculation formula?</h3>
The volume of solvent required to dissolve the provided solute is multiplied by the ratio of the moles of the solute whose molarity has to be computed. (M=frac{n}{V}) The molality of the solution that needs to be computed in this case is M. n is the solute's molecular weight in moles.
Learn more about Molarity:
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